∠ADC = 112°
∠ADC =6x + 7 + 12x - 3
Equate both:
6x + 7 + 12x - 3 = 112
Solve for x :
6x + 7 + 12x - 3 = 112
Combine like terms:
18x + 4= 112
Take away 4 from both sides:
18x = 108
Divide both sides by 18:
x = 6
Find ∠ADB:
6x + 7 = 6(6) + 7 = 43
Answer: ∠ADB = 43°
Answer:
57 units^2
Step-by-step explanation:
First find the area of the triangle on the left
ABC
It has a base AC which is 9 units and a height of 3 units
A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5
Then find the area of the triangle on the right
DE
It has a base AC which is 6 units and a height of 1 units
A = 1/2 bh = 1/2 ( 6) *1 = 3
Then find the area of the triangle on the top
It has a base AC which is 3 units and a height of 3 units
A = 1/2 bh = 1/2 ( 3) *3 = 9/2 = 4.5
Then find the area of the rectangular region
A = lw = 6*6 = 36
Add them together
13.5+3+4.5+36 =57 units^2
Answer:
yes
Step-by-step explanation: