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RideAnS [48]
4 years ago
8

Simplify: 19x – y – 2z + x + 5y + 2z

Mathematics
1 answer:
Alchen [17]4 years ago
5 0

20x+4y. I hope I helped (:

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Answer: 48 pounds of trails mix

Step-by-step explanation:

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What is 99 divided bye 100
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Step-by-step explanation:

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4 years ago
Susan uses the function p(x) = 4x to determine the perimeter of a square when she knows the side length, x. Which statements are
mr_godi [17]

We are given the function p(x) = 4x for the perimeter of the square.

Where x represents the known side length of the square.

x is the independent variable and Perimeter P is the dependent variable on x.

<em>Because value of P total depends on the value of side length x of the square.</em>

Therefore, following statement are true about the given function:

<h3>The perimeter is the dependent variable.</h3><h3>The value of p(x) depends on the value of x.</h3><h3>The length of the side of the square is the independent variable.</h3>
7 0
4 years ago
Use the Empirical Rule to determine the percentage of candies with weights between 0.7 and 0.98 gram. ​Hint: x=0.84
Lubov Fominskaja [6]

Using the Empirical Rule, it is found that 95% of the candies have weights between 0.7 and 0.98 gram.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Researching this problem on the internet, we have that:

  • The mean is of 0.84.
  • The standard deviation is of 0.07.

Then 95% of the candies have weights between 0.7 and 0.98 gram, as:

  • 0.7 = 0.84 - 2 x 0.07.
  • 0.98 = 0.84 + 2 x 0.07.

More can be learned about the Empirical Rule at brainly.com/question/24537145

#SPJ1

7 0
2 years ago
The number of parking tickets issued in a certain city on
Katyanochek1 [597]
I am going to say it is probably ....B....
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4 years ago
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