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3 years ago

Help please thank you

Mathematics

2 answers:

timurjin [86]3 years ago

5 0

Answer:

Freddie Cougar was just hungry so answer is d for deez-nuts Hope this helped.

Step-by-step explanation:

suter [353]3 years ago

3 0

The answer is 5/8.hope this helps

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-18d + 19.09 = -14.46 − 13d − 11.1d

Lilit [14]

d=-5.5 should be the answer

3 0

3 years ago

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Find the missing side length

DochEvi [55]

Tan=o/adj
Tan=60/b
B=60/tan(68)
I don't have a calculator on me but you should be able to do it from there

3 0

3 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

4 0

3 years ago

Solve the system using substitution x=3y-11 4x-3y=-26

iragen [17]

Answer:

x=3y-11

then now putting the value of x in second equation

4(3y-11)-3y =26

12y - 44-3y=26

9y=44+26

9y=70

y=70/9

now putting the value of y in 1st equation then

x=3*70/9-11

x=37/3

now checking this is correct or not in 2nd eqn

4*37/3-3*70/9=26

148-70/3=26

26=26

Step-by-step explanation:

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3 years ago

What type of angle is angle G? A. obtuse B. straight C. acute D. right

lianna [129]

Step-by-step explanation:

the correct answer is c

4 0

3 years ago

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