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3 years ago

30% of a number is one-thirtieth of x, find the initial expression as a fraction of x

1 answer:

7 0

$30\%=\frac{1}{30}x\\\\0.3=\frac{1}{30}x\\\\\frac{3}{10}=\frac{1}{30}x\ \ \ \ \ |\cdot30\\\\x=9\\As\ a\ fraction\ \frac{9}{30}$

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I NEED THIS Which equation represents a line that has a slope of 2 and passes through the point (1,-3)

s2008m [1.1K]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

7. Sorav bought a jacket for Rs. 2500 sold it for Rs. 1900. Find her loss.

Morgarella [4.7K]

Answer:

600

Step-by-step explanation:

if SP>CP,

It is profit [SP - CP = Profit]

if CP>SP,

It is loss [CP - SP = Loss]

Here in the question CP>SP so,

loss = CP - SP

=2500 - 1900

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4 0

3 years ago

Read 2 more answers

The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the tri

son4ous [18]

Answer:

Step-by-step explanation:

8 0

3 years ago

In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s

MaRussiya [10]

Answer:

The mentioned number in the exercise is:

362

Step-by-step explanation:

To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.

If:

x = hundredths digit
y = tens digit
z = ones digit

We can write:

x = z + 1 (the hundreds digit is one more than the ones digit).
y = 2x (the tens digit is twice the hundreds digit).
x + y + z = 11 (the sum of the digits is 11).

Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:

x + y + z = 11
(z + 1) + y + z = 11 (remember x = z + 1)
z + 1 + y + z = 11
z + z +y + 1 = 11 (we just ordered the equation)
2z + y + 1 = 11 (z + z = 2z)
2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
2z + y = 10
2z + (2x) = 10 (remember y = 2x)
2z + 2x = 10
2z + 2(z + 1) = 10 (x = z + 1 again)
2z + 2z + 2 = 10
4z + 2 = 10
4z = 10 - 2
4z = 8
z = 8/4
z = 2

Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:

x = z + 1
x = 2 + 1
x = 3

And we'll use the second equation to obtain the value of y (the tens digit):

y = 2x
y = 2(3)
y = 6

Organizing the digits, we obtain the number:

Number = xyz
Number = 362

As you can see, the obtained number is 362.

8 0

3 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

3 years ago