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Greeley [361]
3 years ago
10

30% of a number is one-thirtieth of x, find the initial expression as a fraction of x

Mathematics
1 answer:
balu736 [363]3 years ago
7 0
30\%=\frac{1}{30}x\\\\0.3=\frac{1}{30}x\\\\\frac{3}{10}=\frac{1}{30}x\ \ \ \ \ |\cdot30\\\\x=9\\As\ a\ fraction\ \frac{9}{30}
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The prism below is made of cubes which measure 1/3 of an inch on one side what is the volume
EastWind [94]

Answer:

Volume of rectangular prism = 10/9 inch³

Step-by-step explanation:

Given:

Size of each cube = 1/3 inch

Find:

Volume of rectangular prism

Computation:

Length of rectangular prism = 2 x [1/3]

Length of rectangular prism = 2/3 inch

Width of rectangular prism = 3 x [1/3]

Width of rectangular prism = 3/3

Width of rectangular prism = 1 inch

Height of rectangular prism = 5 x [1/3]

Height of rectangular prism = 5/3 inch

Volume of rectangular prism = Length x Width X Height

Volume of rectangular prism = [2/3] x [1] x [5/3]

Volume of rectangular prism = 10/9 inch³

7 0
3 years ago
What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)
Pachacha [2.7K]

Answer:

The third option listed: \sqrt[3]{2x} -6\sqrt[3]{x}\\

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

7\sqrt[3]{2x}  -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x}  -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x}  -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}

Therefore this is the simplified radical expression: \sqrt[3]{2x} -6\sqrt[3]{x}\\

5 0
3 years ago
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julsineya [31]
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8 0
3 years ago
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s344n2d4d5 [400]
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
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3=4a+1
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hence the equation will be:
y=1/2(x+2)^2+1


5 0
3 years ago
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astra-53 [7]

Answer:

Step-by-step explanation:

Step-by-step explanation:

15 r blue marbles

20- 5 = 15

3 0
2 years ago
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