QUESTION A
The given multiplication problem is

Factor each term to obtain;

Cancel out the common factors to obtain;

Simplify to get;

QUESTION B
The given multiplication problem is

This the same as

This simplifies to;

QUESTION C
The given problem is

This is the same as


This simplifies to

QUESTION D.
The given expression is

Factor the 54 to obtain;

Cancel the common factors to get;

This simplifies to;

QUESTION E
The given problem is

Convert the mixed numbers to improper fraction to obtain;


Cancel the common factors to get;


QUESTION F
The multiplication problem is

Convert the mixed numbers to improper fractions to obtain;

Cancel out the common factors to get;

Simplify;

QUESTION G
The given problem is

Convert to improper fractions;

Cancel out the common factors to get;


Convert back to mixed numbers

QUESTION H
The given expression is

Convert to improper fraction to get;

Cancel common factors to get;

Simplify

Convert back to mixed numbers;

The value of x is 77 cm which will make the triangles similar by SSS similarity theorem
Given length of the three sides of one triangle are 35 , 20 and 20
and length of the three sides of another triangle are x, 44,44
We need to find the values of x by using SSS Similarity theorem
We know that triangles are are similar by side - side - side similarity creation and hence the sides are in the same ratio
As both the triangles are isosceles triangles
Therefore ,
x/35 = 44/20=44/20 (Using ratio)
Solving the equation we get
x=44*35/20
x= 77
Hence the value of x is 77cm
Learn more about similarity of triangles here brainly.com/question/14285697
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Answer: 52.34
Step-by-step explanation: sin23=opposite/hypotenuse=x/125
sin23/1=x/125
125sin23=x
x=48.841391... add 3.5 = 52.341391... round to 52.34
Answer:
The answer is 15
Step-by-step explanation:
I know and is not stupid
Answer:
The area of the original rectangle = 189 sq ft.
Step-by-step explanation:
Let, the width of the rectangle = m feet
So, the length of the rectangle = (2 m + 3) ft
Now, new width w' = (m + 4)
Perimeter of new rectangle (P') = 68 ft
Perimeter of a rectangle = 2 (LENGTH + WIDTH)
⇒68 ft = 2( L + W')
or, 68 ft = 2 [( 2m + 3) + (m + 4)]
or, 2 (3m + 7) = 68
or, 3m + 7 = 68/2 = 34
⇒ 3m = 34 - 7 = 27
⇒ m = 27/3 = 9
or, m = 9 ft
Hence, the original width of the rectangle = 9 ft
Original Length of the rectangle = 2m + 3 = 2(9) + 3 = 21 ft
Now, Area of the Rectangle = LENGTH X WIDTH
= 21 ft x 9 ft = 189 sq ft
Hence,the area of the original rectangle = 189 sq ft.