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morpeh [17]
4 years ago
14

Find m abc (6x-7) (4x+23)

Mathematics
1 answer:
Salsk061 [2.6K]4 years ago
8 0

Answer:

m∠ABC = 83°

Step-by-step explanation:

The angle ∠abc and ∠dbe are opposed by the vertex. By definition  "<em>Two angles opposite the vertex are congruent or equal</em>"

So ∠abc = ∠dbe

Then, to solve this problem you must match both expressions and clear the variable x.

(6x-7) = (4x + 23)\\6x - 7 -4x = 23\\2x = 30\\x = 15

Now substitute x = 15 in the given expression for the angle ∠abc. (6x-7)

So, we have:

6(15) -7\\= 90 - 7\\= 83\°°

Finally, the angle is 83°

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What value represents the solution of the equation 2 (x+5) = }(2 - 4)?
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Answer:

C -6

step by step explanation:

7 0
3 years ago
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What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1? y = (StartFraction
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By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is \frac{5y_2+y_1}{6}

<h3>What is section formula ?</h3>

Let point P(x,y) cuts line joining point  A(x_1,y_1) and B(x_2,y_2)  in m_1:m_2 then coordinate of point P is equal to (\frac{m_1x_2+m_2x_1}{m_1+m_2}, \frac{m_1y_2+m_2y_1}{m_1+m_2})

Here given that point divides line segment from J to K into a ratio 5:1

So

m_1=5\\\\m_2=1

Now we have to fin y coordinate of point that divides the directed line segment from J to K into a ratio of 5:1

We can calculated y coordinate by applying section formula as :

\frac{5y_2+1y_1}{5+1}\\\\\frac{5y_2+y_1}{6}

By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is \frac{5y_2+y_1}{6}

To learn more about   section formula visit:brainly.com/question/26433769

4 0
3 years ago
HELP PLEASE. 50 POINTS!!
valkas [14]
Answers: 
(1) 
Option (B) 60.
(2) Option (C) 946.4 yd^2.
(3) D<span>egree of the central angle for sector C = </span>126°.


Explanations:
(1) 
The original area of parallelogram is = A = 120

Since
Area-of-parallelogram = (base)(height)
A = bh = 120

Now the base is reduced to one-fourth of its original length and height is doubled. Therefore the new Area will be:
A_{new} = ( \frac{1}{4} b)(2h)

Since bh = 120 (as stated above); therefore:

A_{new} = ( \frac{1}{2} bh)&#10;

A_{new} = ( \frac{1}{2} 120) = 60

So the new Area will be 60.

(2) The area of a regular polygon = Area = (1/2)(apothem) (perimeter). 
perimeter = 8 * (side-length) = 8(14) = 112 yards

(8 because it's octagon)
Area =   (1/2)(apothem) (perimeter)Area =   (1/2)(16.9) (112)Area = 946.4 yd^2
(3) For this you need to know the sector-angle formula:

(Area-of-a-given-sector) / (Total Area) = (Degrees-of-the-central-angle)/(Total-degrees)

Area-of-a-given-sector = 0.35
Total Area = 0.35 + 0.15 + 0.5 = 1.0
Degrees-of-the-central-angle = ?
Total Degree = 360°

Plug in the values in equation:
0.35/1 = (Degrees-of-the-central-angle)/360°

=> Degrees-of-the-central-angle = 0.35 * 360° = 126°

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