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frozen [14]
3 years ago
7

Ronald spins a spinner that has 10 sections numbered from 1 to 10. What is the probability that the spinner lands on a prime num

ber?
A.) 1/10
B.) 2/10
C.) 2/5
D.) 1/2
Mathematics
2 answers:
vladimir1956 [14]3 years ago
5 0
Prime number is a whole number that has no possible divisors that 1 and itself. Prime numbers are 2, 3, 5.7.11,13,17,19,23 and 29. From 1 to 10 there are 3 prime numbers: 3,5 and 7. 
The probability can be calculated as the ratio between the number of "good" events and the total number of possible events. There are three "good" events (3,5 or 7) and 10 total events, so the probability that the spinner lands on a prime number is: 3/10. So, none of the given options is true.
Igoryamba3 years ago
3 0

The answer would be 2/5.

                                                 Hope I helped!! :)

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3 years ago
You're baking a cake with a ratio of 3:4. If you use 2 cups of flour,how many cups of sugar will you use?
Vinil7 [7]

Answer:

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5 0
3 years ago
Is this the correct answer?
Step2247 [10]

Step-by-step explanation:

Close.  You correctly set up the integrals.  When integrating e²ˣ:

∫ e²ˣ dx

½ ∫ 2 e²ˣ dx

½ e²ˣ + C

So the coefficient should be ½, not 2.

[eˣ − ½ e²ˣ]₋₁⁰ + [½ e²ˣ − eˣ]₀¹

[(e⁰ − ½ e⁰) − (e⁻¹ − ½ e⁻²)] + [(½ e² − e) − (½ e⁰ − e⁰)]

1 − ½ − e⁻¹ + ½ e⁻² + ½ e² − e − ½ + 1

-e⁻¹ + ½ e⁻² + ½ e² − e  + 1

8 0
3 years ago
Read 2 more answers
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