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Ugo [173]
3 years ago
11

What is the tangent ratio for ∠E

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
4 0

Answer:  The tangent ratio for angle E is \dfrac{3}{4}.

Step-by-step explanation:  We are given to find the tangent ratio of angle E in the figure.

From the figure, we note that

the triangle DEF is a right-angled triangle, where ∠D = 90° and ∠E is an acute angle.

We know that

tangent ratio of an angle is given by the length of the perpendicular divided by the length of the base associated with that particular angle.

Now, for angle E, we have

perpendicular = DF = 6 units

and

base = DE = 8 units.

Therefore, the tangent ratio for angle E will be

\tan \angle E=\dfrac{perpendicular}{base}\\\\\\\Rightarrow \tan \angle E=\dfrac{DF}{DE}\\\\\\\Rightarrow \tan \angle E=\dfrac{6}{8}\\\\\\\Rightarrow \tan \angle E=\dfrac{3}{4}.

Thus, the tangent ratio for angle E is \dfrac{3}{4}.

Stells [14]3 years ago
3 0
Tan E = 6/8 = 3/4

answer
3/4
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Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =
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Answer:

\sin L = 0.60

tan\ N = 1.33

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Step-by-step explanation:

Given

See attachment

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LN^2 = MN^2 + LM^2

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\sin L = \frac{6}{10}

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tan\ N = \frac{Opposite}{Adjacent}

tan\ N = \frac{LM}{MN}

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Solving (c): \cos L

\cos L = \frac{Adjacent}{Hypotenuse}

\cos L = \frac{LM}{LN}

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