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3 years ago

What is the tangent ratio for ∠E

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

4 0

Answer: The tangent ratio for angle E is $\dfrac{3}{4}.$

Step-by-step explanation: We are given to find the tangent ratio of angle E in the figure.

From the figure, we note that

the triangle DEF is a right-angled triangle, where ∠D = 90° and ∠E is an acute angle.

We know that

tangent ratio of an angle is given by the length of the perpendicular divided by the length of the base associated with that particular angle.

Now, for angle E, we have

perpendicular = DF = 6 units

and

base = DE = 8 units.

Therefore, the tangent ratio for angle E will be

$\tan \angle E=\dfrac{perpendicular}{base}\\\\\\\Rightarrow \tan \angle E=\dfrac{DF}{DE}\\\\\\\Rightarrow \tan \angle E=\dfrac{6}{8}\\\\\\\Rightarrow \tan \angle E=\dfrac{3}{4}.$

Thus, the tangent ratio for angle E is $\dfrac{3}{4}.$

Stells [14]3 years ago

3 0

Tan E = 6/8 = 3/4

answer
3/4

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3 years ago

In a certain school, 6% of all students get a probation due to diverse reasons. Use the Poisson approximation to the binomial di

photoshop1234 [79]

Answer:

Step-by-step explanation:

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3 years ago

If sin theta= - 5/7, which of the following are possible?

Sphinxa [80]

Answer:

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Step-by-step explanation:

$\text{Use:}\\\\\sin^2\theta+\cos^2\theta=1\to\cos\theta=\pm\sqrt{1-\sin^2\theta}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\\\\\sec\theta=\dfrac{1}{\cos\theta}\\\\==========================\\\\\sin\theta=-\dfrac{5}{7}\\\\\cos\theta=\pm\sqrt{1-\left(-\frac{5}{7}\right)^2}=\pm\sqrt{1-\frac{25}{49}}=\pm\sqrt{\frac{24}{49}}=\pm\dfrac{\sqrt{24}}{\sqrt{49}}=\pm\dfrac{\sqrt{24}}{7}\\\\\sec\theta=\pm\dfrac{1}{\frac{\sqrt{24}}{7}}=\pm\dfrac{7}{\sqrt{24}}$

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3 years ago