(f+g)(x)=f(x)+g(x)
(f+g)(x)=3x+4+8x+1
(f+g)(x)=11x+5
(f+g)(0)=11(0)+5
(f+g)(0)=0+5
(f+g)(0)=5
Answer:
u = 40° , v = 40° and x = 100°
Step-by-step explanation:
i) from the rule of triangle we know that the sum of all three angles = 180°
ii) 100° + 40° + y = 180°. Therefore y = 40°. where y is the angle adjacent to v.
iii) from theorem on parallel lines we can say that u = y =40°
iv) from the properties of parallel lines we get v = 40° as interior alternate angles are equal.
v) again from the properties of parallel lines we get u = 40°
vi) using the triangle property as in i) we can see that u + v + x =180° therefore 40° + 40° + x = 180°. Therefore x = 100°.
vii) Therefore u = 40° , v = 40° and x = 100°
Y = -8x - 5/4......slope here is -8 or -8/1
y = 1/8x + 4/5...slope here is 1/8
what u have here are negative reciprocal slopes....negative reciprocal of a number can be found by flipping the number and changing the sign. So the negative reciprocal of -8/1 is 1/8 (see how I flipped the number and changed the sign)...and when u have negative reciprocal slopes, this means that ur lines are perpendicular.
Yes, 16.3 is y maybe but or else I need to use a protractor I believe
Answer:
2,789ft
Step-by-step explanation:
The set up will give a right angled triangle.
The altitude will be the opposite side = 1600 ft
The angle of depression = 35°
approximate direct distance to the stadium is the hypotenuse of the trisngle= x
Using the SOH trig identity to get the distance
sin 35 = opp/hyp
sin 35 = 1600/x
x = 1600/sin35
x = 1600/0.5736
x = 2,789.4ft
Hence mai’s approximate direct distance to the stadium is 2,789ft
