For this case we are going to define the original coordinates:
(x, y): original coordinates.
We apply the transformation:
(x, y) -------> (-x, y + k)
We have:
-x: reflection on the y axis.
y + k: translation k units up.
Answer:
The point was reflected over the y-axis and translated up.
Hello from MrBillDoesMath!
Answer:
x^3 - 6 x^2 - x + 6
Discussion:
The polynomial is
(x-1) (x - (-1)) (x-6) =
(x-1)(x+1)(x-6) = => as (x-1)(x+1) = x^2 - 1
(x^2-1)(x-6) =
x^2(x) - 6 x^2 - 1x + 6 =
x^3 - 6 x^2 - x + 6
Thank you,
MrB
Answer: q³⁰
Explanation:
First just solve the first part using the exponent rules
p²q⁵ becomes 1/p-⁸q-²⁰ then we flip the fraction so the exponents become positive. Now we have p⁸q²⁰.
Before multiplying the other equation, we must simplify. p-⁴q⁵ becomes 1/p⁴q-⁵ and since it's the exponents being raised to a power we simply multiply the inner exponents times the outer exponent which yields 1/p⁸q-¹⁰. We must make q-¹⁰ positive so we will then bring it to the numerator of the fraction which gives us: q¹⁰/p⁸.
Multiply q¹⁰/p⁸ * p⁸q²⁰/1 = p⁸q³⁰/p⁸ divide the p exponents by each other which yields 0 since when u divide exponents you just subtract them so 8 - 8 = 0. Your answer is now q³⁰/1 or just q³⁰
A cardboard box rests on the floor of an elevator. The box has a mass m = 3.75 kg and the elevator has an upward acceleration of a
Part a. Select the Free Body Diagram for the system
Part b. Write an expression for the sum of the forces actinv on the box in the y direcion, given that up is the positive y direction. Your answer should be in terms of FN, m, g.
Part c. Write an expression for the normal force FN, that the block experiences in terms of the elevator's accelaration, the block's mass and the accelaration of gravity
Part d. If the elevator's accelaration has a magnitude of g in the downward direction, what would the normal force FN1 be in Newtons? (Numerical value)
Part e. If the elevator's accelaration had a magnitude of g in the upward direction, what would the normal force FN2 ve in Newtons? (Numerical value)
