Answer:
0.05 is a terminating decimal
Step-by-step explanation:
0.05 is a terminating decimal because it has finite digits.
Answer:
The system if equation that can be used to derive this are
6x + 4y = 69 AND
12x + y = 96
The price of a drink is $7.5
Step-by-step explanation:
The question here says that Taylor and Nora went to the movie theater and purchase refreshments for their friends. Taylor spends a total of $69.00 on 6 drinks and 4 bags of popcorn Nora spends a total of $96.00 on 12 drinks and bag of popcorn.And we are now told to write a system of equations that can be used to find the price of one drink and the price of one bag of popcorn. Using these equations,we should determine and state the price of a drink, to the nearest cent .
Now, Let's assume that the price of a drink is "X" and that of a bag of popcorn to be Y
The first person made a purchase which led to the equation
6x + 4y = 69______ equation 1
And the second person also made a purchase that lead to the equation
12x + y = 96_____ equation 2
We make y the subject of the formula in equation 2 and apply it in 1
Y = 96 - 12x
Now apply the above in equation 1
6x + 4y = 69
6x + 4(96 - 12x)= 69
6x + 384 - 48x = 69
42x = 384 - 69
X = 315/42
X = 7.5
Substitute x= 7.5 in equation 2
12x + y = 96
12(7.5) + y = 96
90 + y = 96
Y = 6
Therefore, the price of a drink is $7.5
Answer:
-8 and 1
Step-by-step explanation:
Answer:
Step-by-step explanation:
In the first pattern, there were 6 sticks
In the second pattern, there were 10 sticks.
In the third pattern, there were 14 sticks.
Based on the pattern, we see that each time, 4 more sticks are added and that the initial amount of stick is 6.
Thus: the equation for how many sticks there would be in pattern n is:
# of sticks in pattern n = 6 + 4n
Hope that helps!
the Highest common factor of 130,260,390 = 130
130 = 2⋅5⋅13
260 = 2⋅2⋅5⋅13
390 = 2⋅3⋅5⋅13
Common multipliers (130; 260; 390): 2, 5, 13
Now to find the highest Common factor you need to multiply the common factors
Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130
