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Lelechka [254]
3 years ago
12

For every pound a company spends on advertising, it spends £0.59 on its website. Express the

Mathematics
2 answers:
Verizon [17]3 years ago
7 0

Answer:

100:59

Step-by-step explanation:

For every pound a company spends on advertising, it spends £0.59 on its website.

Amount Spent on Advertising = £1

Amount Spent on Website = £0.59

Therefore:

Amount Spent on Advertising : Amount Spent on Website

= 1 : 0.59

Multiply both sides by 100

= 100: 59

The ratio of the amount spent on advertising to its website as a ratio in its simplest form is 100:59 in its simplest form.

Rufina [12.5K]3 years ago
6 0

Answer:

£100 : £59

Step-by-step explanation:

The said company spends £0.59 on its website for every pound spent on advertisement. This implies that out of £1.00 spent on advertisement by the company, £0.59 is for website placements.

Thus, the rate of the amount spent on advertisement to amount spent on website is given as:

             £1.00 : £0.59

To convert this to the nearest whole number, multiply through by 100, so that the ratio becomes;

£100.00 : £59.00

Therefore, the ratio expressed in its simplest form is £100 : £59

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La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?
malfutka [58]

Answer:

Falso.

Step-by-step explanation:

Sea d = \frac{a}{b} un número racional, donde a, b \in \mathbb{R} y b \neq 0, su opuesto es un número real c = -\left(\frac{a}{b} \right). En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) <em>El exponente es cero.</em>

(b) <em>El exponente es un negativo impar.</em>

(c) <em>El exponente es un negativo par.</em>

(d) <em>El exponente es un positivo impar.</em>

(e) <em>El exponente es un positivo par.</em>

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, c = d = 1. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

d' = d^{-n} y c' = c^{-n}

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

d' = \left(\frac{a}{b} \right)^{-n} y c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}

d' = \left(\frac{a}{b} \right)^{(-1)\cdot n} y c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}

d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}y c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}

d' = \left(\frac{b}{a} \right)^{n} y c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}

d' = \left(\frac{b}{a} \right)^{n} y c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}

d' = \left(\frac{b}{a} \right)^{n} y c' = \left[-\left(\frac{b}{a} \right)\right]^{n}

Si n es impar, entonces:

d' = \left(\frac{b}{a} \right)^{n} y c' = - \left(\frac{b}{a} \right)^{n}

Puesto que d' \neq c', la proposición es falsa.

(c) El exponente es un negativo par.

Si n es par, entonces:

d' = \left(\frac{b}{a} \right)^{n} y c' = \left(\frac{b}{a} \right)^{n}

Puesto que d' = c', la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

d' = d^{n} y c' = c^{n}

d' = \left(\frac{a}{b}\right)^{n} y c' = \left[-\left(\frac{a}{b} \right)\right]^{n}

d' = \left(\frac{a}{b} \right)^{n} y c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}

d' = \left(\frac{a}{b} \right)^{n} y c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}

Si n es impar, entonces:

d' = \left(\frac{a}{b} \right)^{n} y c' = - \left(\frac{a}{b} \right)^{n}

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

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Answer:

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S = sandy shores

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1/8 = .125

30% = .30

.45

Smallest to largest

.125 <.30 <.45

1/8 < 30% < .45

Changing to percent form

12.5%, 30% ,45%

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