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3 years ago

Please answer quick!!!

Mathematics

2 answers:

sergey [27]3 years ago

6 0

Answer:

$\huge\boxed{IQR = 30}$

Step-by-step explanation:

Q1 = 130 (Left hand edge of the box)

Q3 = 100 (Right Hand edge of the box)

Interquartile Range = Q3-Q1

IQR = 130-100

IQR = 30

Sidana [21]3 years ago

4 0

Answer:

A. 30

Step-by-step explanation:

The interquartile range for a box and whiskers plot, is the value from the right side of the box minus the value of the left side of the box.

In this case at the far right side of the box it is at 130, at the far left side of the box it is at 100.

130-100=30

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Add -3 5/6 + 5 3/7 A.) 1 25/42 B.) 2 8/13 C.)-9 11/42 D.) 1 27/42

Fantom [35]

Answer:

A. 1 25/42

Step-by-step explanation: =-3 5/6 +5 3/7

= (-23/6)+ (38/7)

=(-161+228)/42

=-67/42

8 0

3 years ago

How do I solve this

ra1l [238]

-2+(-5)=-7 and 6+(-3)=3

5 0

3 years ago

Which of the following is equal to 4 2/3 / 3 1/2?(If you think its the answer I picked in the picture, its not) Thank you so muc

bazaltina [42]

Answer:

Step-by-step explanation:

4 2/3= 12/3+2/3=14/3

3 2/1=7/2 but you have to flip it

so you end up with 14/3*2/7

5 0

3 years ago

Read 2 more answers

Math ... answer meeee

zloy xaker [14]

You need to find the GCF (greatest common factor) of 45 and 90, which is 45.

45 times ? gets you 45

? would be 1

45 times 1 equals 45.

45 times ? gets you 90

? would be 2

45 times 2 equals 90

45(1+2) = 45+90 = 135

♡ Hope this helps! ♡

❀ 0ranges ❀

7 0

3 years ago

Read 2 more answers

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng

gladu [14]

${\bold{\red{\huge{\mathbb{QUESTION}}}}}$

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

$\bold{ \red{\star{\blue{GIVEN }}}}$

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

$AREA = ANGLE \: \: IN \: \: RADIAN \times RADIUS$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

Total Area Of The Semi Sphere:-

$AREA = \pi \times radius \\ \\ AREA = \pi \times 2 = 2\pi$

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

$AREA = \frac{\pi}{3} \times radius \\ \\ AREA = \frac{\pi}{3} \times 2 \\ \\ AREA = \frac{2\pi}{3}$

$\green{Now:- } \\ \green{ \: Area \: Under \: Unshaded \: Part }$

Total Area - Area Under Unshaded Part

$Area= 2\pi - \frac{2\pi}{3} \\ Area = \frac{6\pi - 2\pi}{3} \\ Area = \frac{4\pi}{3} \: \: ans$

$\red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star$

5 0

2 years ago