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natita [175]
3 years ago
6

Please answer quick!!!

Mathematics
2 answers:
sergey [27]3 years ago
6 0

Answer:

\huge\boxed{IQR = 30}

Step-by-step explanation:

Q1 = 130 (Left hand edge of the box)

Q3 = 100 (Right Hand edge of the box)

Interquartile Range = Q3-Q1

IQR = 130-100

IQR = 30

Sidana [21]3 years ago
4 0

Answer:

A. 30

Step-by-step explanation:

The interquartile range for a box and whiskers plot, is the value from the right side of the box minus the value of the left side of the box.

In this case at the far right side of the box it is at 130, at the far left side of the box it is at 100.

130-100=30

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3 years ago
(7z^3+42z^2-15z+1)- (36z^2+12z-21)​
My name is Ann [436]

Answer:

7z^3+6z^2-27z+22

Step-by-step explanation:

The given question is of subtraction:

So,

(7z^3+42z^2-15z+1)- (36z^2+12z-21)​

=7z^3+42z^2-15z+1-36z^2-12z+21

Combining alike terms to simplify

=​7z^3+42z^2-36z^2-15z-12z+1+21

=7z^3+6z^2-27z+22

So the answer in simplified form is:

7z^3+6z^2-27z+22 ..

6 0
3 years ago
Read 2 more answers
Simplify: 3 . 3^2 + 8 ÷ 2 - (4 + 3) A: 32 B: 24 C: 23 D: 30
yaroslaw [1]

Answer:

its none of these answers ;-;

Step-by-step explanation:

3^2 + 8 ÷ 2 - (4 + 3)

we do what's in parentheses first. (pemdas)

so now we have, 3^2 + 8 ÷ 2 - 7

next exponents, 3^2=9

9 + 8 ÷ 2 - 7

next division, 8÷2=4

9 + 4 - 7

next addition, 9+4=13

13-7

finally subtraction, 13-7=6

final answer: 6

7 0
3 years ago
For what value of the domain {–3, –1, 0, 2, 5} does f(x) = g(x) When f(x) = 3x – 4 and g(x) = x2 – 2
zavuch27 [327]
F(x) = g(x)
3(2) - 4 = (2)² - 2
6 - 4 = 4 - 2
2 = 2
I just substituted all the values in the domain to see which one would work. That's not really the quickest way but that's the only way I know

7 0
3 years ago
The line is given by equation y–1.5x = c. What is the value of c if the line passes through the point K (2, –3).
aleksandr82 [10.1K]

Answer:

c = -6

Step-by-step explanation:

To find the value of c to make the line pass through the point K = (2, -3), we just need to use the values of x = 2 and y = -3 in the equation, then we find the value of c.

So, we have that:

y - 1.5*x = c

(-3) - 1.5 * (2) = c

-3 - 3 = c

c = -6

So the value of c is -6

To check if the value is correct, we can use the value x = 2 and see if the value of y is -3:

y - 1.5*x = -6

y - 1.5*2 = -6

y - 3 = -6

y = -6 + 3 = -3

So it's correct.

7 0
3 years ago
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