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igor_vitrenko [27]
2 years ago
5

Pls answer correctly! Thank you : )

Mathematics
2 answers:
mamaluj [8]2 years ago
5 0
I don’t see the question
stellarik [79]2 years ago
4 0
I don’t see the question???
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4 years ago
Solve to find x <br> log (3x+5) to base 5= 2log (1-3x) to base 25
Eduardwww [97]

Answer:

x = -2/ 3

Step-by-step explanation:

in order to cancel out the logs they should have common bases

\mathsf{ log_{5}(3x + 5) = 2 log_{25}(1 - 3x)  }

we can write 25 as 5²

\mathsf{ \implies  log_{5}(3x + 5) =  2 \: log_{ {5}^{2} }(1 - 3x)  }

we know that the reciprocal of the exponents of the bases are multiplied to the log

\mathsf{ \implies  log_{5}(3x + 5) =   \frac{1}{\cancel{2} } \times \cancel{2} \: log_{ 5}(1 - 3x)  }

and now since the logs have common bases

\mathsf{ \implies  \cancel { log_{5}}(3x + 5) = \cancel{ log_{ 5}}(1 - 3x)  }

we're left with

\mathsf{ \implies 3x + 5 = 1 - 3x}

\mathsf{ \implies 9x = -4}

<u>x = -2/ 3</u>

8 0
3 years ago
Which expression is equivalent to –3(u+7)<br> PLEASE ANSWER THE QUESTION
Andreyy89

Answer: (u+7) x -3

I like to use substitution, for example u=2

(2+7) x -3 = -27

-3(2+7) = -27

5 0
3 years ago
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