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3 years ago

Write 680,750 in expanded form

Mathematics

2 answers:

Nataly [62]3 years ago

8 0

In expanded form, the answer would look like this:

600,000 + 80,000 + 700 + 50

Rama09 [41]3 years ago

3 0

600,000+80,000+700+50

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Find a rational number halfway between 7/8 and 6/7

algol [13]

<h3>Answer: 97/112</h3>

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How to get this answer:

Midpoint formula: (A+B)/2 = C

A and B are the endpoints with C as the midpoint

A = 7/8

B = 6/7

A+B = 7/8 + 6/7

A+B = 49/56 + 48/56

A+B = (49+48)/56

A+B = 97/56

(A+B)/2 = (97/56) divided by 2

(A+B)/2 = (97/56) times (1/2)

(A+B)/2 = (97*1)/(56*2)

(A+B)/2 = 97/112

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3 years ago

In a class of 62 students, the number of females is one less than twice the number of males. How many females and how many males

lawyer [7]

Hopefully i helped you.

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3 years ago

GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?

loris [4]

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

$2n-1=14$

solve for n

$2n=14+1$

$2n=15$

$n=7.5\ cm$

step 2

Find the length of GJ

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

$GJ=\frac{1}{2}DE$

we have

$GE=2n+1=2(7.5)+1=16\ cm$

substitute

$GJ=\frac{1}{2}16=8\ cm$

step 3

Find the length of HK

we have that

$HK=\frac{1}{2}GJ$ ----> by the midpoint theorem

we have

$GJ=8\ cm$

substitute

$HK=\frac{1}{2}8=4\ cm$

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3 years ago

How do you rewrite quadratic equations

disa [49]

A quadratic should be in the form ax²+bx+c=0
where a b and c are all numbers

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1.27 reapeating as a fraction

Ahat [919]

1.27 = 1 27/100
I hope this helps!

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