All categories

3 years ago

Write 680,750 in expanded form

Mathematics

2 answers:

Nataly [62]3 years ago

8 0

In expanded form, the answer would look like this:

600,000 + 80,000 + 700 + 50

Rama09 [41]3 years ago

3 0

600,000+80,000+700+50

You might be interested in

Is this question proportional? why or why not

sergij07 [2.7K]

No because the cost to ship a video game starts at 4.85 but if it were to start at zero than I would because it consistently adds 39.99.

8 0

3 years ago

What is the simplified expression

gizmo_the_mogwai [7]

Answer:

the answer is the first -5cd

5 0

3 years ago

Is a graph a proportional

Bogdan [553]

Answer:

How to tell the difference: A proportional graph is a straight line that always goes through the origin. A non-proportional graph is a straight line that does not go through the origin.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What's the next answer in BADEHGJK

alina1380 [7]

BADEHGJK NM because it's going backwards and then it skips a letter

3 0

3 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

3 years ago