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Yuki888 [10]
3 years ago
13

Which symbol makes the following number sentence true? 546, 322. 540, 997

Mathematics
2 answers:
Reil [10]3 years ago
8 0
The answer is:
545>322
540 <997
cluponka [151]3 years ago
8 0

Answer:

a)546 > 322

b)540 < 997

Step-by-step explanation:

We need to compare the given number

a) We have 546 and 322

We clearly know that 546 is a larger number than 322.

Thus, we could use the greater than symbol to compare them.

546 > 322

b) We have 540 and 997

We clearly know that 540 is a smaller number than 997.

Thus, we could use the smaller than symbol to make the comparison.

540 < 997

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The diagram shows the sports played by 80
-BARSIC- [3]

Answer:

wheres the diagram

Step-by-step explanation:

3 0
3 years ago
How to solve 76×327 step by step
hram777 [196]

Here's a method that takes advantage of the values of these particular numbers.

... 76 = 80 - 4

so

... 76 × 327 = (80 -4)×327

... = 80×327 - 4×327

Repeated doubling will give us values that are 2, 4, and 8 times 327.

... 2×327 = 327+327 = 654

... 2×654 = 4×327 = 654+654 = 1308 . . . . we'll use this later

... 2×1308 = 8×327 = 2616

We want 80×327, so we can add a zero to the end of this last:

... 80×327 = 26160

Now, we can subtract 4×327 to get 76×327

... 80×327 - 4×327 = 26160 -1308 = 24852 = 76×327

_____

More conventionally, you would multiply every digit of one number by every digit of the other and add the products according to their respective place values.

327 × 076 = (3×0)×10000 + (3×7 +2×0)×1000 +(3×6 +7×0 +2×7)×100 +(2×6 +7×7)×10 +(7×6)×1

... = 0 +21,000 +3,200 + 610 +42

... = 24,852

Note the pattern of partial products here. This is a method taught to/by practitioners of Vedic mathematics, and can be done in your head. At most, you would write down the partial product sums 21, 32, 61, and 42 to keep from having to carry more than one number in your head at a time.

5 0
3 years ago
( simultaneous equations)
daser333 [38]

Answer:

See method below.

Step-by-step explanation:

m/n + n/3 = 2

2/m + n = 4    

First  eliminate the fractions by multiplying the first equation by 3n:-

3m + n^2 = 6n...........(1)

and the second equation by m:-

2 + mn = 4m..............(2)

Now we solve using substitution:-

From equation  (2):-

4m - mn = 2

m = 2 / (4 - n)

Now substitute for m in equation (1):-

6/ (4 - n) + n^2 = 6n

6 + n^2(4 - n) = 6n(4 - n)

6 + 4n^2 - n^3 = 24n - 6n^2

n^3 - 10n^2 + 24n - 6 = 0

This will not factor so we could solve this using graphical software.

To find the values of the variable m we substitute the found values of n into one of the original equations and solve for m.






6 0
3 years ago
May someone help me with this following question I already know it's not (B)
dybincka [34]

Answer:

a

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help me fast please!
velikii [3]

Answer:

10^6

Step-by-step explanation:

The reason is because 2x5 = 10 and then you add the exponents when multiplying, making it 10^8

7 0
2 years ago
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