Answer: y/x = 1
Step-by-step explanation:
It was on quizlet
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Answer with explanation</u>
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Let
be the distance traveled by deluxe tire .
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since
is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.
Test statistic : 
where, n= sample size
= sample mean
= Population mean
=sample standard deviation
For
, we have

By using z-value table,
P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]
=1-0.9871=0.0129
Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .
[We reject the null hypothesis when p-value is less than the significance level .]
Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.
Answer:
68.
Step-by-step explanation:
The common difference d = -19 - (-22) = 3
So the 31st term =
a31 = -22 + (31-1)3
= -22 + 90
= 90 - 22
= 68.
Using .25N, you set N equal to 18 for 18 quarters. so .25(18) = 4.50
Let success be that a plant dies in the winter and failure be that a plant survives the winter, then
p = 0.05, q = 1 - 0.05 = 0.95
a.) P(1 or more will not survive the winter) = 1 - P(all will survive the winter) = 1 - P(0) = 1 - 10C0 (0.05)^0 (0.95)^10 = 1 - 1(1)(0.5987) = 0.4013
b.) P(all will survive) = P(none will die) = P(0) = 0.5987