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3 years ago

In the division problem 18+ 3 = 6, is 18 the quotient divisor dividend remainder

Mathematics

2 answers:

MissTica3 years ago

8 0

Answer:

Dividened

Step-by-step explanation:

Because that is what is going into 3

have a great day!

brailiest is appreciated!

ryzh [129]3 years ago

5 0

That’s not a division symbol, it’s a sum, but assuming you meat to put the division symbol, 18 would be the dividend

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Let t=number of years since 1991.
Then
P(t)=147 e^(kt) ... in millions
P(0)=147 e^(0)=147
P(7)=147 e^(7k)=153
e^(7k)=(153/147)
take ln both sides
ln(e^(7k))=ln(153/147)
7k=0.0400 => k=0.005715

Year 2017=>t=2017-1991=26
P(26)=147e^(26*.005715)=170.55
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Find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one

ziro4ka [17]

The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

<h3>What is the probability?</h3>

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

No of failure,n = 7

No of trials,x≥6

A binomial probability is represented as;

$\rm P(x) = nC_x p^z(1-p)^{n-r}$

Substitute the given data;

$P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}$

$\rm P(x \geq 6) = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%$

Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

To learn more about probability, refer to the link: brainly.com/question/795909.

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