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3 years ago

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\sqrt{3x + 5} " alt="y = \sqrt{3x + 5} " align="absmiddle" class="latex-formula">

2 answers:

kenny6666 [7]3 years ago

7 0

Hey there

the answer is

sveticcg [70]3 years ago

6 0

$y=\sqrt{3x+5}\\\\The\ domain:\\\\3x+5\geq0\ \ \ |-5\\\\3x\geq-5\ \ \ |:3\\\\x\geq-\dfrac{5}{3}\to x\in\left[-\dfrac{5}{3};\ \infty\right)$

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F(x)= 7.45x +33.7 at x=-4.3

weeeeeb [17]

To solve this function, all we need to do is substitute -4.3 in for wherever "x" appears and then simplify.

f(x) = 7.45x + 33.7; x = -4.3

f(-4.3) = 7.45(-4.3) + 33.7

f(-4.3) = -32.035 + 33.7

f(-4.3) = 1.665

This means that, when x = -4.3, f(x) = 1.665.

Note: It may help to remember that, in a function such as this, f(x) can be thought of as the "y" value that corresponds to the given "x" value (in fact, when writing it out with words, f(x) is the same as "function of x"). And, if you are given a value for f(x), then the opposite is true. Just substitute in the value given for f(x) and solve for x.

Hope this helps!

8 0

4 years ago

A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome

Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

$=P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135$

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

$=P(X$

Thus, the probability that the flight has empty seats is 0.4625.

4 0

3 years ago

Which situation can be represented by this equation? <br> 2,500 + 40x = 7,300-60x

koban [17]

Answer:

x= 48

Step-by-step explanation:

$2500+40x+60x=7300\\40x+60x=7300-2500\\100x=7300+2500\\100x=4800\\x=4800/100\\x=48$

4 0

3 years ago

PLEASE HELP!!!!! I DON'T UNDERSTAND!!

Roman55 [17]

Answer: Pool Size

(in feet) 3.5 ft

Avg Depth 4 ft

Avg Depth 4.5 ft

Avg Depth 5 ft

Avg Depth

12x24 7,600 8,600 9,700 10,800

14x28 10,300 11,800 13,200 14,700

15x30 11,800 13,500 15,200 16,900

16x32 13,400 15,400 17,300 19,200

18x36 17,000 19,400 21,900 24,300

19x38 19,000 21,700 24,400 27,100

20x40 21,000 24,000 27,000 30,000

22x44 25,400 29,000 32,700 36,300

25x45 29,531 33,750 37,968 42,187

25x50 32,800 37,500 42,200 46,900

30x50 39,375 45,000 50,525 56,250

Step-by-step explanation:I made this chart for you so you can know actually how to multiply the width of the pool.

6 0

3 years ago

PLZ ans have mocks plz

Yanka [14]

Answer:

The table will be:

x |-2 | -1 | 0 | 1 | 2

y | 1 | 4 | 5 | 4 | 2

Step-by-step explanation:

The function is:

$y=5-x^{2}$

a) The x values of the table is:

x |-2 | -1 | 0 | 1 | 2

So, when x = -2, y will be:

$y(-2)=5-(-2)^{2}=5-4=1$

Doing the same with the other x values we have:

$y(-1)=5-(-1)^{2}=5-1=4$

$y(0)=5-(0)^{2}=5$

$y(1)=5-(1)^{2}=5-1=4$

$y(2)=5-(2)^{2}=5-4=1$

The table will be:

x |-2 | -1 | 0 | 1 | 2

y | 1 | 4 | 5 | 4 | 1

I hope it helps you!

5 0

3 years ago