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Helga [31]
3 years ago
6

Mr. John Doe was figuring out his federal income tax. His income was $26,800, but he was able to subtract $5,500 in deductions.

He paid 15% of the remaining income tax. How much did he pay?
Mathematics
1 answer:
kumpel [21]3 years ago
7 0
The answer is 
5.70

Mr. John Doe was figuring out his federal income tax. His income was $26,800, but he was able to subtract $5,500 in deductions. He paid 15% of the remaining income tax. How much did he pay?
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During the trip, the Morales family drove on several different highways. Gabriela and Luis noticed that sometimes the mile marke
Elenna [48]

<u><em>Answer:</em></u>

The slope of the line is 77

<u><em>Explanation:</em></u>

We know the speed is constant and that the mile-marker location over time can be represented by a line. This means that the equation is linear.

<u>The slope can, therefore, be calculated as follows:</u>

slope = \frac{y_2-y_1}{x_2-x_1}

where (x₁ , y₁) and (x₂ , y₂) are two points on the line

We are given that the two points (1, 123) and (3, 277) are two points in the line

<u>Substitute with them in the above equation to get the slope as follows:</u>

slope = \frac{277-123}{3-2}=77

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3 0
2 years ago
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores
KengaRu [80]

Answer:

The 95% confidence interval for the difference of means is (7.67, 16.33).

The estimate is Md = 12.

The standard error is sM_d = 2.176.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (this year's sales), of size n1=36 has a mean of 53 and a standard deviation of 12.

The sample 2 (last year's sales), of size n2=49 has a mean of 41 and a standard deviation of 6.

The difference between sample means is Md=12.

M_d=M_1-M_2=53-41=12

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{36}+\dfrac{6^2}{49}}\\\\\\s_{M_d}=\sqrt{4+0.735}=\sqrt{4.735}=2.176

The degrees of freedom are:

df=n_1+n_2-1=36+49-2=83

The critical t-value for a 95% confidence interval and 83 degrees of fredom is t=1.989.

The margin of error (MOE) can be calculated as:

MOE=t \cdot s_{M_d}=1.989 \cdot 2.176=4.328

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 12-4.328=7.67\\\\UL=M_d+t \cdot s_{M_d} = 12+4.328=16.33

The 95% confidence interval for the difference of means is (7.67, 16.33).

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2 years ago
26s? + 33<br> Submit<br> Hzhjskapskdjsjababah
kipiarov [429]

Answer:

59

Step-by-step explanation:

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Johnny was walking down the street and he found 20$ so he went into the shop and bout three ice cream cones boxes how much money
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Step-by-step explanation:

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