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Simora [160]
3 years ago
7

How do you factor 20x^2 - 66x +54 ?

Mathematics
1 answer:
yarga [219]3 years ago
3 0
There is a way to factor with a leading coefficient larger than 1, but first, it would be easier to factor out a number to make the next steps easier.
2(10x²-33x+27) ← Factor out a 2, then just temporarily drop it to make things less messy

So now we have 10x²-33x+27. The first step when factoring with a leading coefficient is to multiply the leading coefficient (10) and the constant (27) = 270. Then, we find the factors of 270 and see what would add to give -33.
The factors are -15 and -18

Then, we get (10x²-15x)+(-18x+27)
Factor out a 5x from the first, and -9 from the second
5x(2x-3)-9(2x-3)
That would give us (5x-9)(2x-3) but don't forget the 2 from above! Therefore, the final answer is:
2(5x-9)(2x-3)
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Answer:

$502.96 to $597.04

Step-by-step explanation:

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The lower and upper bound for a 95% confidence interval are given by:

U=\mu +1.960*\frac{\sigma}{\sqrt{n}}\\L=\mu -1.960*\frac{\sigma}{\sqrt{n}}

Applying the given data:

U=550 +1.960*\frac{120}{\sqrt{25}}\\U= \$597.04\\L=550 -1.960*\frac{120}{\sqrt{25}}\\L= \$502.96

The 95% confidence interval is $502.96 to $597.04.

3 0
3 years ago
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Answer

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Step-by-step explanation:

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c

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I solved this by simply doing 11,000 x 4% x 15 which brings you to 72600.

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Step-by-step explanation:

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