Answer: 
Step-by-step explanation:
You can reduce the fractions, then:
Rewrite them as following:
If you subtract the first number and the second number, you obtain:
If you subtract the second number and the second number, you obtain:
Therefore, you must subtract 
and to obtain the number asked. Then, this is:
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
Answer:
center=(-7,5)
Step-by-step explanation:
The center form of the circle equation is in the format (x – h)^2 + (y – k)^2 = r^2, with the center being at the point (h, k).
you can find center by making equal to zero each term, then:
x+7 = 0
x=-7
y-5 = 0
y=5
then the center is (-7,5).
