All categories

3 years ago

Maya cut 3 1/4 yards of fishing line from a new reel. How much is this in inches

Mathematics

1 answer:

ikadub [295]3 years ago

6 0

1 yard = 3 feet:

3.25 yards x 3 feet per yard = 9.75 feet.

1 foot = 12 inches:

9.75 feet x 12 inches per foot = 117 inches.

You might be interested in

If 15 baseballs weighs 75 ounces how many baseballs with 15 ounces

igor_vitrenko [27]

Answer:

Step-by-step explanation:

75/15=5

Bam

5 0

3 years ago

Leo bought 6 chew toys for his new puppy each chew toy cost $4 how much did Leo spend for the chew toys

Nikolay [14]

6*4 equals 24 bam easy mat

8 0

3 years ago

Read 2 more answers

Help me pleaseeeeeee

bekas [8.4K]

It’s b

it has to be 20 c long … kskdhdhiIakakkwdydyxiajajshsuuaisudj

7 0

3 years ago

Find the remainder when x⁴+x³-2x²+x+1 divided by x+1

Zolol [24]

Answer:

$\frac{-2}{x+1}$

Step-by-step explanation:

$x^3-2x+3-\frac{2}{x+1}$

also if ur brainly staff and seeing this

plz remove/delete my account asap tysm

5 0

3 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago