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leva [86]
2 years ago
15

Which of the following expressions represent 15% tip on a $20 meal? Which represents the total bill? **Select all that apply**.

Explain your reasoning for the choices you select.
A.) 1520
B.) 20+0.1520
C.) 1.1520
D.) 1510020
Mathematics
1 answer:
kifflom [539]2 years ago
4 0

Answer:

15/100 * 20, because the meal is 20 dollars and to find the percent of something you divide it with 100 so you will divide 15 with 100 and you’ll get 0.15. Then you will times it with the amount the meal cost because thats the charge. So 0.15•20 and you’ll get $3. A 15% tip for a $20 meal is $3.

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If students’ scores were normally distributed and the mean was 200 with a standard deviation of 40, then what is the probability
Sonja [21]

Answer:

  84%

Step-by-step explanation:

The empirical rule tells you that 68% of the standard normal distribution is within 1 standard deviation of the mean. The distribution is symmetrical, so the amount in the lower tail is (1 -68%)/2 = 16%.

Since the number you're interested in, 240, is one standard deviation above the mean (200 +40), the percentage of interest is the sum of the area of the central part of the distribution along with the lower tail:

  68% + 16% = 84%.

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3 years ago
Jeremy swims 5 3/5 kilometers in a 7 day period. He swims the same distance each day. What distance does he swim?
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Since 5 3/5 can be turned into 28/5, then divided by 7/1, you will get 4/5. So Jeremy swims 4/5 of a kilometer each day.
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3 years ago
Read 2 more answers
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
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Svetach [21]
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Masja [62]

Answer:

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Step-by-step explanation:

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