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hammer [34]
3 years ago
11

A set of composite numbers less than 12 .express it in listing and set builder methods​

Mathematics
1 answer:
marusya05 [52]3 years ago
5 0

Given:

A set of composite numbers less than 12.

To find:

The set by listing and set builder methods​.

Solution:

Composite number: A positive integer is called a composite number if it has at least one divisor other than 1 and itself.

Composite numbers less than 12 are 4, 6, 8, 9, 10.

By using the listing method , the given set can be expression as:

Set = {4, 6, 8, 9, 10}

The numbers 4, 6, 8, 9, 10 are greater than 1, less than 12 and non prime numbers.

By using set builder method, the given set can be expression as:

Set = \{x|x\neq P,1

Therefore, the list and set builder notation of the given set are {4, 6, 8, 9, 10} and \{x|x\neq P,1 respectively.

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4:X is equivalent to 24:12<br> X=???
Elena-2011 [213]

Answer:

X=2

Step-by-step explanation:

Ratios

4:x = 24:12

24:12 reduced is 2:1

Therefore we can see x must be half of 4.

So the answer is 2

Hope this helps! :)

pls mark brainiest

6 0
3 years ago
Read 2 more answers
Help thank you very much​
charle [14.2K]

Answer:

B: 76

Step-by-step explanation:

I have to put an explanation.I don't have an explanation.

6 0
3 years ago
What is the binomial expansion of (x 2y)7? 2x7 14x6y 42x5y2 70x4y3 70x3y4 42x2y5 14xy6 2y7 x7 14x6y 42x5y2 70x4y3 70x3y4 42x2y5
AysviL [449]

You can take x = a, 2y = b and then can apply the binomial theorem.

The expansion of given expression is given by:

Option D: x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7 is

<h3>What is binomial theorem?</h3>

It provides algebraic expansion of exponentiated(integer) binomial.

According to binomial theorem,

(a+b)^n = \sum_{i=0}^n ^nC_i a^ib^{n-i}

<h3>How to use binomial theorem for given expression?</h3>

Taking a = x, and b =2y, we have n = 7, thus:

(x+2y)^7 = \: ^7C_0x^0(2y)^7 + \: ^7C_1x^1(2y)^6 + \: ^7C_2x^2(2y)^5 + \: ^7C_3x^3(2y)^4 + \:^7C_4x^4(2y)^3 + \:^7C_5x^5(2y)^2 + \:^7C_6x^6y^1 + \: ^7C_0x^7y^0\\\\&#10;(x+2y)^7 = 128y^7 + 448xy^6 + 672x^2y^5 + 560x^3y^4 + 280x^4y^3 + 84x^5y^2 + 14x^6y + x^7\\\\&#10;(x+2y)^7 = x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7

Thus, Option D: x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7 is correct.

Learn more about binomial theorem here:

brainly.com/question/86555

6 0
3 years ago
Find the domain and range with a vertex of (1,-2)
klemol [59]

Answer:

see explanation

Step-by-step explanation:

the domain ( values of x ) that a quadratic can have is all real numbers

domain : - ∞ < x < ∞

the range ( values of y ) are from the vertex upwards , that is

range : y ≥ - 2

3 0
2 years ago
Please answer now fast
miss Akunina [59]

Answer:

∠2

Step-by-step explanation:

A supplementary angle is a 180° angle formed by two angles. ∠3 and ∠2 form a straight line / 180° angle.

5 0
3 years ago
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