You have to derive for a multiplication in both terms:
=e^x+xe^x-(e^x-1 + (x-2)e^x-1) now apply distributive property in the last term:
=e^x+xe^x+e^x-1-xe^x-1 now replace each x by 0 (x=0)
=1 + 0 + e^-1 + 0 = 1+ e^-1 = 1.3679
Answer:
1020000is a hundredth tenths thousands
<span>constant sum = 4 + 5 = 9</span>
Answer:
it is in the attic
Step-by-step explanation:
