Answer:
<h2>(1, 1)</h2>
Step-by-step explanation:
![(x,\ y)\\\\\text{Put thecoordinates of the points to the equation of}\ f(x)\ \text{and check the equality}:\\f(x)=\dfrac{1}{2}(2)^x\\\\(0,\ 1)\to x=0,\ y=1\\L=1\\R=\dfrac{1}{2}(2)^0=\dfrac{1}{2}(1)=\dfrac{1}{2}\\\\L\neq R\\\\(0,\ 2)\to x=0,\ y=2\\L=2\\R=\dfrac{1}{2}\\\\L\neq R\\\\\left(1;\ \dfrac{1}{2}\right)\to x=1,\ y=\dfrac{1}{2}\\L=\dfrac{1}{2}\\R=\dfrac{1}{2}(2)^1=\dfrac{1}{2}(2)=1\\\\L\neq R\\\\(1,\ 1)\to x=1,\ y=1\\L=1\\R=1\\\\L=R](https://tex.z-dn.net/?f=%28x%2C%5C%20y%29%5C%5C%5C%5C%5Ctext%7BPut%20thecoordinates%20of%20the%20points%20to%20the%20equation%20of%7D%5C%20f%28x%29%5C%20%5Ctext%7Band%20check%20the%20equality%7D%3A%5C%5Cf%28x%29%3D%5Cdfrac%7B1%7D%7B2%7D%282%29%5Ex%5C%5C%5C%5C%280%2C%5C%201%29%5Cto%20x%3D0%2C%5C%20y%3D1%5C%5CL%3D1%5C%5CR%3D%5Cdfrac%7B1%7D%7B2%7D%282%29%5E0%3D%5Cdfrac%7B1%7D%7B2%7D%281%29%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5CL%5Cneq%20R%5C%5C%5C%5C%280%2C%5C%202%29%5Cto%20x%3D0%2C%5C%20y%3D2%5C%5CL%3D2%5C%5CR%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5CL%5Cneq%20R%5C%5C%5C%5C%5Cleft%281%3B%5C%20%5Cdfrac%7B1%7D%7B2%7D%5Cright%29%5Cto%20x%3D1%2C%5C%20y%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5CL%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5CR%3D%5Cdfrac%7B1%7D%7B2%7D%282%29%5E1%3D%5Cdfrac%7B1%7D%7B2%7D%282%29%3D1%5C%5C%5C%5CL%5Cneq%20R%5C%5C%5C%5C%281%2C%5C%201%29%5Cto%20x%3D1%2C%5C%20y%3D1%5C%5CL%3D1%5C%5CR%3D1%5C%5C%5C%5CL%3DR)
Answer:
(A)
![C_n=3+2n](https://tex.z-dn.net/?f=C_n%3D3%2B2n)
(B)
![C_1_0=23](https://tex.z-dn.net/?f=C_1_0%3D23)
Step-by-step explanation:
(A)
we are given
![C_n_+_1=C_n+2](https://tex.z-dn.net/?f=C_n_%2B_1%3DC_n%2B2)
![C_1=5](https://tex.z-dn.net/?f=C_1%3D5)
Firstly, we will find few terms
![C_2=C_1+2](https://tex.z-dn.net/?f=C_2%3DC_1%2B2)
![C_2=5+2](https://tex.z-dn.net/?f=C_2%3D5%2B2)
![C_2=7](https://tex.z-dn.net/?f=C_2%3D7)
![C_3=C_2+2](https://tex.z-dn.net/?f=C_3%3DC_2%2B2)
![C_3=7+2](https://tex.z-dn.net/?f=C_3%3D7%2B2)
![C_3=9](https://tex.z-dn.net/?f=C_3%3D9)
![C_4=C_3+2](https://tex.z-dn.net/?f=C_4%3DC_3%2B2)
![C_4=9+2](https://tex.z-dn.net/?f=C_4%3D9%2B2)
![C_4=11](https://tex.z-dn.net/?f=C_4%3D11)
so, we will get terms as
5, 7 , 9 , 11
we can see that this is arithematic sequence
First term =5
common difference =d=7-5=2
now, we can use nth term formula
![C_n=C_1+(n-1)d](https://tex.z-dn.net/?f=C_n%3DC_1%2B%28n-1%29d)
now, we can plug values
![C_n=5+2(n-1)](https://tex.z-dn.net/?f=C_n%3D5%2B2%28n-1%29)
![C_n=5+2n-2](https://tex.z-dn.net/?f=C_n%3D5%2B2n-2)
![C_n=3+2n](https://tex.z-dn.net/?f=C_n%3D3%2B2n)
(B)
we can plug n=10
![C_1_0=3+2\times 10](https://tex.z-dn.net/?f=C_1_0%3D3%2B2%5Ctimes%2010)
![C_1_0=23](https://tex.z-dn.net/?f=C_1_0%3D23)
To find the denominator:
3+6=9
There are 3 shades of blues so our fraction is 3/9
To get the percent you multiply 3/9×100/1=300/9
300÷9=33.33%
33.33 rounded to the nearest percent is 33%.
Your answer is 33%.
The answer to the first is a^2
0.0277777778 but for a power idk
8^1
d^0
and if e = 2 then the answer is 0.5 but idk power
The value of a lower quartile is always the start of the box making your answer the number 2