Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
Answer:
Visit geogebra.com
Step-by-step explanation:
none needed <3
Answer:
Option A is the correct answer.
Explanation:
Any vector can be resolved in to two components. Horizontal component and vertical component.
Consider a vector F which is at angle θ⁰ to the horizontal, we can resolve this vector in to two.
Horizontal component = F cos θ
Vertical component = F sin θ
Here we have Force , F = 50 pounds
Angle with horizontal = 80°
Horizontal component = F cos θ = 50* cos 80 = 8.68 pounds
≅ 9 lb.
Option A is the correct answer.
Answer: infinitely many solutions.
Step-by-step explanation:
Ok, our equation is:
-2.1*b + 5.3 = b - 3.1*b + 5.3
now, simplifyng the right side, we have:
b - 3.1*b + 5.3 = (1 - 3.1)*b + 5.3 = -2.1*b + 5.3
Then our initial expression is:
-2.1*b + 5.3 = -2.1*b + 5.3
So in both sides of the equality we have the exact same thing, so this is a trivial equality.
This means that the equality will remain true for any value of b, which means that we have infinitely many solutions.
Answer:
650
Step-by-step explanation:
lets say the # of standard version is x and the # of high-quality version is y
x+y=1060
2.5x+4.8y=3593
solve the system
y=410
x=650