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stealth61 [152]
3 years ago
5

How do some families use their credit cards?

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0
They use it for house,clothes,food,and other stuff they can buy it with
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The sum of three consecutive odd integers is –87. What are the integers?
nirvana33 [79]
-30 -29 -28 is the correct answer



8 0
2 years ago
A country has 32 parks that allow camping and 43 parks that have playgrounds. Of those, 10 parks both allow camping and have pla
Olenka [21]

Answer:

25

Step-by-step explanation:

Given:

32 parks allow camping

43 parks allow playgrounds

10 parks both allow camping and playgrounds

110 total parks

First, we need to add 32, 43, and 10

32 + 43 + 10 = 85

Then, we find the difference of 110 and 85

110 - 85 = 25

Since it isn't a decimal, there is no point in rounding.

8 0
3 years ago
Helppppppppppp plsssssss n ty
Alexus [3.1K]

Answer:

C. \frac{1}{8}

C. \frac{1}{32}

Step-by-step explanation:

A unit fraction is a fraction that has 1 as it's numerator and a positive number as it's denominator.

5 0
2 years ago
Read 2 more answers
The base of an aquarium with given volume V is made of slate and the sides are made of glass. If slate costs five times as much
Y_Kistochka [10]

Answer:

x = ∛ 2*V/5  

y = ∛ 2*V/5

h  = V/ ∛ 4*V²/25

Step-by-step explanation:

Dimensions of the aquarium base is  x*y

We call c₁ cost per unit area of the sides, then cost per unit area of slate is equal 5c₁.

let call h the height of the aquarium then volume of the aquarium is:

V = x*y*h      where   h =  V / x*y

As the base is a rectangular one there are 2 sides x*h .  and 2 sides  y*h

According to this:

Ct (cost of aquarium )  = cost of the base  + cost of the sides

cₐ  ( cost of the base) = 5*c₁*x*y

c₆ (cost of the sides ) = c₁*2*x*h   +   c₁*2*y*h

C(t)  =  5*c₁*x*y +2* c₁*x* V/x*y  +  2* c₁*y* V/x*y    or

C(t)  =  5*c₁*x*y  + 2*c₁*V/y   *2*c₁* V/x

Taking partial derivatives en x and y we have:

C´(x)  =  5*c₁*y - 2*c₁*V/x²

C´(y)  =  5*c₁*x - 2*c₁*V/y²

C´(x)  = C´(y)        ⇒  5*c₁*y - 2*c₁*V/x²  =   5*c₁*x - 2*c₁*V/y²

or    5*y - 2*V/x²  =   5*x - 2*V/y²

(5*y*x² - 2*V)/x²  = ( 5*y²x - 2*V) /y²

(5*y*x² - 2*V)*y²  = ( 5*y²x - 2*V)*x²

5*y³*x² - 2*V*y²  =  5*y²x³  - 2*V*x²

5*y³*x² - 5*y²x³  =  2*V * ( y² - x²)

by symmetry  x =  y

Then using x = y  and plugging that value on the derivatives

C´(x) =  5*c₁*y - 2*c₁*V/x²

C´(x) =  5*c₁*x - 2*c₁*V/x²

C´(x) = 0          ⇒     5*c₁*x - 2*c₁*V/x²  = 0

5*x  - 2*V/x² = 0      ⇒  5*x³ - 2*V = 0   ⇒   5*x³  = 2*V  ⇒ x³ = 2*V/5

x = ∛ 2*V/5       and   y = ∛ 2*V/5    and   h  =  V/ x*y    h  = V/ ∛ 4*V²/25

7 0
3 years ago
Which function has zeros at x = 10 and x = 2? A f(x) = x2 – 12x + 20 B f(x) = x2 – 20x + 12 C f(x) = 5x2 + 40x + 60 D f(x) = 5x2
kow [346]
You have to set it up as two problems then combined like terms then add them together 

8 0
3 years ago
Read 2 more answers
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