Answer:
H. 260
Step-by-step explanation:
We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.
14 tables * 14 students = total students
196 = total students ( for those fourteen tables)
Now we also know that sixteen students can sit on the rest of the cafeteria tables.
We need to find the number of tables can hold sixteen students.
To do this, we'll lead with a simple equation:
18 tables total - 14 tables = # of remaining tables
4 = # of remaining tables
Now we're going to do the same thing we did with the original tables:
4 tables * 16 students = total students
64 = total students
Finally, we add both of the tables max values together:
64 + 196 = 260
Answer:
3. [1, −2]
2. [−3, 3]
1. [−7, 10]
Step-by-step explanation:
3.
{7⁄2x - ½y = 9⁄2
{3x - y = 5
-6⁄7[7⁄2x - ½y = 9⁄2]
{−3x + 3⁄7y = −3 6⁄7 >> New Equation
{3x - y = 5
_________________
-4⁄7y = 1 1⁄7
-2 = y [Plug this back into both equations above to get the x-coordinate of 1]; 1 = x
__________________________________________________________
2.
{−3x + 9y = 36
{4x + 12y = 24
¾[4x + 12y = 24]
{−3x + 9y = 36
{3x + 9y = 18
______________
18y = 54
___ ___
18 18
y = 3 [Plug this back into both equations above to get the x-coordinate of −3]; −3 = x
__________________________________________________________
1.
{4x − y = −38
{x + y = 3
_____________
5x = -35
___ ____
5 5
x = -7 [Plug this back into both equations above to get the y-coordinate of 10]; 10 = y
I am joyous to assist you anytime.
Is there a picture for this
2 1/6 divided by 7/10
13/6 / 7/10 =
13/6 * 10/7 =
130/42 =
3 4/42. or 3 2/21 hours... three and two twenty-firsts
