What is the value of (3x^2+1-1-x)(2) ?

Mathematics

1 answer:

Dafna1 [17]3 years ago

7 0

Answer:

6x^2 -2x

Step-by-step explanation:

As written, the constant terms in the first factor cancel each other. The distributive property is used to perform the multiplication:

(3x^2 +1 -1 -x)(2) = (3x^2 -x)(2) = (3x^2)(2) -x(2)

= 6x^2 -2x

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Kyle drew three line segments with lengths: 2/4 inch 2/3inch, and 2/6 inch list the fractions in order from least to greatest

Sati [7]

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Method 1
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Since the numerators are the same, the smaller the denominators, the greater the fraction is.

Arranging from the least to the greatest
$\dfrac{2}{6} \ , \ \dfrac{2}{4} \ , \ \dfrac{2}{3}$

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Method 2
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Lets change all to the same denominators

$\dfrac{2}{4} = \dfrac{2 \times 3}{4 \times 3} = \dfrac{6}{12}$

$\dfrac{2}{3} = \dfrac{2 \times 4}{3 \times 4} = \dfrac{8}{12}$

$\dfrac{2}{6} = \dfrac{2 \times 2}{6 \times 2} = \dfrac{4}{12}$

Now that all the denominators are the same, we can arrange the fractions by comparing the numerators. The bigger the numerators, the greater the fraction.

Arranging from the least to the greatest
$\dfrac{2}{6} \ , \ \dfrac{2}{4} \ , \ \dfrac{2}{3}$

3 0

3 years ago

Read 2 more answers

The perimeter of a rectangle must be less than 156 feet. If the length is known to be 66 feet, find the range of possible widths

balu736 [363]

x = perimeter

x<156

length = 66

so, in order to calculate perimeter you need to add two lengths and two widths

156 (perimeter) - 2 (66) = two widths

156 - 132 = 24 (remember this number is two widths added together)

so 24 twice the width SO 12 would be the number that the width can't be larger than