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Annette [7]
4 years ago
11

Please can you help me with this math problem

Mathematics
2 answers:
makvit [3.9K]4 years ago
8 0
First multiply 3 times x+1.
And you will get (3x+3)/2=3. Then multiply 3x2. Then you have 3x+3=6. Substract 3 to 6 and divide over 3. And you will get x=1
galina1969 [7]4 years ago
4 0
I believe the answer is 1.

Hope that helps!!!
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5) The perimeter of the given square is 56cm. Construct an equation and hnd
Shtirlitz [24]

Answer:

side = 14 cm

Step-by-step explanation:

Let 'x' be the side of the square.

Perimeter = 4 * side

                = 4*x

                = 4x

4x = 56

Solution:

4x = 56

Divide both sides by 4

x = 56/4

x = 14 cm

3 0
3 years ago
I need help with 6, 7 and 8 please!
hichkok12 [17]
6. 150 degrees
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6 0
4 years ago
The expression was rewritten using the ( blank?) <br> i’m so confused pls help
RSB [31]

I am solving the equation in simplest way

Line:-1

\\ \tt\bull\longmapsto 9.(7+1)

  • Solve the bracket

\\ \tt\bull\longmapsto 9(8)

\\ \tt\bull\longmapsto 72

Line:-2

\\ \tt\bull\longmapsto 9.7+9.1

\\ \tt\bull\longmapsto 63+9

\\ \tt\bull\longmapsto 72

3 0
3 years ago
Read 2 more answers
A woman made $45,000 during the first year of her new job at city hall. Each year she received a 10% raise. Find her total earni
kati45 [8]
Equation: 45000(1+.1)^6

Answer: 79720.25

Explanation:

This is a prime example of a Compound Interest Formula based question. Due to the fact the question states that the woman is getting a raise every year, we add one rather than subtracting one. Next we convert the 10% into a decimal form into 0.1 and from there since the time is all the same we wouldn’t need to divide anything out so we raise the equation to the sixth power and our final answer is $79720.25
5 0
4 years ago
Identify the expressions for which limits exist.
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Limits exist for:

\lim_{x \to4 \4} \frac{x^2 -x-12}{4-x} = \frac{(x-4)(x+3)}{4-x} = ( - 1 )( x + 3 ) = - 7

\lim_{x \to \ 2} \frac{x^2 +2x-8}{2-x} = \frac{(x+4)(x-2)}{2-x} = ( - 1 )( x + 4 ) = - 6

\lim_{x \to2 } \frac{x^2 +3x - 10}{x^2 -4} = \frac{(x+5)(x-2)}{(x+2)(x-2)} = \frac{x+5}{x+2} = \frac{7}{4}

5 0
2 years ago
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