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Licemer1 [7]
3 years ago
7

Manuel noticed that his cellphone bill reflected a monthly fee of

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

Answer: (total amount paid - $40) / 0.05

Step-by-step explanation:

Given the following :

Monthly fee = $40

Additional fee = $0.05 per minute on phone

Given the the amount paid for the month is available, number of minutes he was on phone can be determined thus :

Total amount to be paid = monthly fee + additional fee

Additional fee = $0.05 × n

Where n = number of minutes on phone

Hence,

Total amount paid = $40 + $0.05n

If the amount paid is known, the number of minutes on phone can be calculated thus;

(Total amount paid - monthly fee) = $0.05n

n = (Total amount paid - monthly fee) / fee per minute on phone

(total amount paid - $40) / 0.05

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To increase and decrease an amount by 7%, what single multiplier would you use?
Mila [183]

We will solve the problem for both cases:


Case 1:

If the amount increases by 7% we have the number for which we are going to multiply is given by:

x = (\frac{1}{100}) * (100 + 7)

x = (\frac{1}{100}) * (107)\\x = 1.07


Case 2:

If the amount decreases by 7% we have the number for which we are going to multiply is given by:

x = (\frac{1}{100}) * (100-7)

x = (\frac{1}{100}) * (93)\\x = 0.93


Answer:

single multiplier you would use for each case is:

x = 1.07 (increase)

x = 0.93 (decrease)

6 0
4 years ago
Read 2 more answers
I don't understand this. Please help!:::: Provide an answer for a, b, c, and d.
OleMash [197]
Answer for part A is  \angle A \cong \angle D which in English means "angle A is congruent to angle D"

The reason why we know that angle A and angle D are congruent is because they are both right angles. By the right angle congruence theorem (the reason just below the blank for part A), we can say that angle A = angle D. They are both 90 degree angles. 

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Answer for the blank in part B is "Given" without quotation marks of course. This is the first "given" while the second given is coming up in part C

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For part C, the other given is \angle C \cong \angle F so that's what will go in the blank. It may seem silly, but all we're doing is repeating verbatim what is given to us. With any proof, you always start with what you are given and somehow connect it with what you're trying to prove

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Finally, the answer for the blank in part D is "AAS Congruence Theorem" (without quotes)

The AAS congruence theorem allows us to prove two triangles congruent if we know if two pairs of angles are congruent plus if we know two sides are congruent as well.

The angle portions are covered by part A and part C. The side portions are part B's territory. Combining A, B, & C allows us to use the AAS theorem

Note: It is NOT the ASA theorem because the two angles do not sandwich the sides. In other words, the side AB is not between the two angles A and C. Similarly, DE is not between the two angles D and F. The order is very important as ASA is slightly different than AAS. 

8 0
3 years ago
Which statement is true regarding the intervals where the function is increasing and decreasing? The function is increasing from
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Answer:

The function is increasing from (- infinity , 0)

Step-by-step explanation:

7 0
3 years ago
The Leukemia and Lymphoma Society sponsors a 5K race to raise money. It receives $55 per race entry and $10,000 in donations, bu
tester [92]
<span>x = number of entries 55x + 10000 - 15x ≥ 55000 First, subtract 10000 from each side 55x - 15x ≥ 45000 Now, we can combine 55x and 15x because they've both got the same variable attached 40x ≥ 45000 Now divide each side by 40 to isolate x (which is the number of entries) x ≥ 1125 The race needs at least 1125 entries to raise at least $55,000.</span>
5 0
3 years ago
A. Use the roster method to write the given set. You may need to consult a reference, such as the Internet or an encyclopedia. (
jarptica [38.1K]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

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\{0,1,2,3,4,5,6,7,8\}

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{x | x is the positive square number less than or equal to 81}

For point C:

All given sets were equal and equal, that since elements and the element no. are identical.

7 0
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