Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.
No , the order in which the members of the committee are chosen is not important.
Step-by-step explanation:
Given : The total number of students in the council = 30
The number of students needed to be chosen = 5
The order in which the members of the committee are chosen does not matter.
So we Combinations (If order matters then we use permutations.)
The number of combinations of to select r things of n things = 
So the number of ways a committee of 5 students can be chosen from a student council of 30 students=

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.
Hello from MrBillDoesMath!
Answer:
(x^4-2) (x^4 -1)
Discussion:
Let u = x^4, then
x^8 - 3x^4 + 2
= u^2 - 3u + 2
= (u -2) ( u -1)
= (x^4-2) (x^4 -1)
Thank you,
MrB
Answer:
See explanation below.
Step-by-step explanation:
a) c(0) = 10
Here, t = 0 and c(0) = 10
At 8 A.M., there are 10 customers.
b) c(6) = c(7)
6 hours after 8 am is 2pm
7 hours after 8 am is 3pm
They are equal. So it means
There are the same number of customers at 2pm and at 3pm
c)
c(k) = 0
There are no customers, k hours after 8 am
d)
c(4) > c(3)
4 hours after 8 am is 12pm
3 hours after 8 am is 11am
This means:
The number of customers at 12pm is greater than the number of customers at 11am
I think it is the first one