The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>
Let x be the speed of the walkway.
(2.8 + x) = speed of child moving in direction of the walkway
(2.8 - x) = speed of child moving against the direction of the walkway
Travel time = distance/speed
Travel time of child moving in direction of walkway = 23/(2.8+x)
Total elapsed time given = 29s
23/(2.8 + x)+ 23 / (2.8-x) = 29
LCD = (2.8 + x)(2.8 - x)
![23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)](https://tex.z-dn.net/?f=23%282.8%20-%20x%29%20%2B%2023%282.8%20%2B%20x%29%20%3D%2029%282.8%20%2B%20x%29%282.8%20-x%29)
simplifying the equation, we get
![23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)](https://tex.z-dn.net/?f=23%2A2.8-23x%2B23%2A2.8%2B23x%3D29%282.8%5E2-x%5E2%29)
![23(2.8+2.8)/29=2.8^2-x^2](https://tex.z-dn.net/?f=23%282.8%2B2.8%29%2F29%3D2.8%5E2-x%5E2)
![x^2=(2.8)^2-(23*5.6)/29)=3.4](https://tex.z-dn.net/?f=x%5E2%3D%282.8%29%5E2-%2823%2A5.6%29%2F29%29%3D3.4)
![x=\sqrt{3.4}=1.84m/s](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B3.4%7D%3D1.84m%2Fs)
Speed of walkway = 1.84 m/s
The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
To learn more about Speed refer to:
brainly.com/question/4931057
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