1 answer:
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Answer:
see attached
Step-by-step explanation:
Rotation 270° counterclockwise is equivalent to rotation 90° clockwise. The transformation of coordinates is ...
(x, y) ⇒ (y, -x) . . . . . . . rotation 270° CCW
This means the points are moved to ...
A(-2, 1) ⇒ A'(1, 2)
B( 1, 2) ⇒ B'(2, -1)
C(-2, 4) ⇒ C'(4, 2)
The rotated triangle is shown in the attachment. You may notice that A' and B are the same point.
Since all the variables cancel out and the coefficient equal to eachother, this system of equation has <u>infinitely many solutions!</u>
Answer:
The speed in of the plane is 115.47 m/sec
Step-by-step explanation:
Given:
Height at which the plane is flying = 6000 m
Angle of elevation at the radar base = 30 Degrees
Angle of elevation at the radar base after one minute = 60 Degrees
To Find:
The Speed of the plane in meter per second = ?
Solution:
Let us use the tangent of the angle to find the distance (d) to a point directly below plane:
<u>when the angle is 30 degrees</u>
d1 = 10392.3 meters
<u>when the angle is 60 degrees</u>
d2 = 3464.1 meters
<u>distance travelled by aircraft in 1 min is </u>
=>d1 - d2
=>0392.3 - 3464.1
= 6928.2 m/min
<u>Now converting to m/sec</u>
=>
=>115.47 m/sec