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Bumek [7]
3 years ago
9

This is due by 12:00 please help

Mathematics
2 answers:
julsineya [31]3 years ago
4 0

Answer:

Step-by-step explanation:

\frac{1}{x^{n} } =x^{-n}

vivado [14]3 years ago
3 0
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Write the fraction in simplest form 4/12
GaryK [48]
4/12= 2/6=1/3 So the answer is 1/3
4 0
3 years ago
Complete the square to solve the equation below.
Vinil7 [7]

9514 1404 393

Answer:

  B.  x = -6, x = 4

Step-by-step explanation:

The constant on the left wants to be 1, the square of half the x-coefficient. We can get it to be that value by adding 8 to the equation.

  x² +2x +1 = 25

  (x +1)² = 25 . . . . . . . rewrite the left side as a square

  x +1 = ±√25 = ±5 . . . . take the square root

  x = -1 ±5 . . . . . . . . . subtract 1

  x = -6 or x = 4

3 0
3 years ago
The hourly wage increase each employee receives each year depends on their number of years of service. Every three years of serv
dimulka [17.4K]

Answer:

B

Step-by-step explanation:

The wording in the problem statement is ...

... "less than 3 years"

... "at least 3. but less than 6 years"

so we expect the inequality symbols to look like ...

... 0 ≤ x < 3

... 3 ≤ x < 6

These match <em>the second piecewise function</em>.

3 0
3 years ago
Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively. How many times will t
Evgen [1.6K]

Answer:

60 times will they ring together at the same second in one hour excluding the one at the end.

Step-by-step explanation:

Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.

To find : How many times will they ring together at the same second in one hour excluding the one at the end?

Solution :

First we find the LCM of 3, 6, 10, 12 and 15.

2 | 3  6  10  12  15

2 | 3  3   5   6  15

3 | 3  3   5   3  15

5 | 1    1  5   1    5

  | 1    1   1   1     1

LCM(3, 6, 10, 12,15)=2\times 2\times 3\times 5

LCM(3, 6, 10, 12,15)=60

So, the bells will ring together after every 60 seconds i.e. 1 minutes.

i.e. in 1 minute they rand together 1 time.

We know, 1 hour = 60 minutes

So, in 60 minute they rang together 60 times.

Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.

6 0
3 years ago
Nine subtracted from the product of 3 and a number is less than 23
kipiarov [429]

Answer:

3n-9<23

You can use any variable you want for n

6 0
3 years ago
Read 2 more answers
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