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raketka [301]
3 years ago
15

In a ABC, BD is perpendicular to AC.The dimensions are shown in centimeters. What is the lenght, in centimeters, of AC?

Mathematics
1 answer:
liq [111]3 years ago
4 0
I need to know the dimensions to solve. Ex: "Line AC is 2.5 centimeters"
My bad - should've asked that under "Ask For Details."
Sorry :(
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Li made a scale drawing of a room. The scale used was 5cm=1m.The scale drawing is the preimage and the room is the dilated image
AleksandrR [38]
Scale in terms of cm to m= 1/5
In every meter there are 5 cm

Considering this, if the dimensions are 15cm and 20cm, you would need to multiply them by 5 to convert them to meters

15*5= 75 20* 5=100

Dimensions- 75ft by 100ft
5 0
3 years ago
6 to power 8 / 6 to power of 6 equals what does the slash mean. How do I calculate
artcher [175]

Step-by-step explanation:

From your problem statement, I believe the equation will look like this:

\frac{6^{8}}{6^{6}}

The slash means "divided by" -- you should use division to solve this equation.

For division involving exponents with the same base, you can use the following rule:

\frac{A^{x}}{A^{y}} = A^{x - y}

Subtituting 6 for A, 8 for x and 6 for y, we get the following:

\frac{6^{8}}{6^{6}} =6^{8 - 6} = 6^{2} = 36

3 0
3 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Georgia [21]

Answer:

Step-by-step explanation:

Given that minimum is 8 and maximum equals 82

Range = 84-8 = 76

No of classes =6

Class width = 76/6 ~13

But not given whether variable is discrete or continuous.

If discrete, we have classes as

8-20, 21-33, 34-46, 47-59, 60-72, 73-85

If continuous, we have classes as

8 to <21

21 to <34

and ... ending 73-<86

7 0
3 years ago
How many terms are in the expression 5x^2-3x+2?
Jlenok [28]

There are 3 terms, 5x^2, -3x, and 2

6 0
3 years ago
Read 2 more answers
What’s the solution to this equation 2+x=7/8x-15
Nostrana [21]

Answer:x=−136

Step-by-step explanation: Step 1: Simplify both sides of the equation.

2+x=

7

8

x−15

2+x=

7

8

x+−15

x+2=

7

8

x−15

Step 2: Subtract 7/8x from both sides.

x+2−

7

8

x=

7

8

x−15−

7

8

x

1

8

x+2=−15

Step 3: Subtract 2 from both sides.

1

8

x+2−2=−15−2

1

8

x=−17

Step 4: Multiply both sides by 8.

8*(

1

8

x)=(8)*(−17)

6 0
2 years ago
Read 2 more answers
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