All categories

3 years ago

Which of the following equations, represents the line with a slope of 2/3 and a y-intercept of 9?

Mathematics

1 answer:

notka56 [123]3 years ago

8 0

Step-by-step explanation:

Equation of line:

$y = mx + c$

where m is the slope

and c is the y-intercept

given the information from the question,

m = 2/3 , c = 9

substituting the values in,

equation of the line is

$y = \frac{2}{3} x + 9$

You might be interested in

20 points!

Sveta_85 [38]

Translations, rotations, and reflections are all rigid transformations.

8 0

3 years ago

Read 2 more answers

The sum of two consecutive odd integers is 56. what is the smaller number?

pentagon [3]

56÷2=28
28-1=27
so the smaller number is 27

5 0

3 years ago

Please Help). Use the figure below to answer the questions. A) Describe in words a sequenc of transformations that maps □ABC to

lesya [120]

Answer:

See below

Step-by-step explanation:

The initial ordered-pairs are $(x, y)$

We have a rotation of 90 degrees counterclockwise with respect to origin

Note. Previously the points were

$A(-3, 4), B(-3, 0), C(-1, 3)$

After the rotation, we have

$A(-4, -3), B(0, -3), C(-3, -1)$

Thus, $(x, y) \rightarrow (-y, x)$

Then shifting horizontally to the right 2 units, we get ΔA'B'C'

Thus,

$(x, y) \rightarrow (-y, x) \rightarrow (x+2, y)$

7 0

3 years ago

Distribution property 18+45

kvv77 [185]

Answer:

Simplified: its 63 then to 3² · 7

Step-by-step explanation:

3 0

3 years ago

Ian is a phycologist interested in determining the proportion of algae samples from a local rivulet that belonged to a particula

pickupchik [31]

Answer: 16590

Step-by-step explanation:

The formula we use to find the sample size is given by :-

, where p = prior estimate of population proportion.

$z^*$ = Critical z-value (Two- tailed)

E= Margin of error .

Let p be the population proportion of cyanobacteria.

Given : E = 0.01

Critical value for 99% confidence interval : $z^*=2.576$

If Ian does not want to rely on previous knowledge , then we assume p=0.5 because the largest standard error is at p=0.5.

Now, the required sample size = $n=0.5(1-0.5)(\frac{2.576}{0.01})^2$

$n=0.25(257.6)^2=0.25(66357.76)=16589.44\approx16590$

Required sample size = 16590

5 0

3 years ago