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2 years ago

5

Analyze the diagram to complete the statements.

1 answer:

svetoff [14.1K]2 years ago

4 0

Answer:

What are your answer choices?

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What is the value of x in the equation

seraphim [82]

1/3 x - 1/2 = 18 1/2
1/3 x = 19 (add 1/2 on the right side to 18 1/2)
x = 57 (multiply the reciprocal of 1/3 and that will be 3/1 or 3 to 19 to get x by itself)
So, the answer is x = 57 (d. 57)

6 0

3 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

2 years ago

Simplify<br> Please thanks

solmaris [256]

Answer: - 6xy/23xy

Step-by-step explanation:

They're both simplified by 11.

8 0

2 years ago

!!WILL MARK BRAINLIEST!!

iren2701 [21]

Answer:

4) 8

Step-by-step explanation:

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2 years ago

Read 2 more answers

(Multiple choice geometry proof) 15 points

Aleksandr-060686 [28]

Answer:

In order:

f

a

c

d

e

b

7 0

2 years ago