Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
18% trust me i got you bro
V≈1436.76
V=4/3
V= 4/3 3.14*
V=1436.75504
Rounded answer is 1436.76
0.32
Simply divide 32 into 100 and get 0.32
you could put it into a calculator or write it out and divide.