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lys-0071 [83]
4 years ago
14

If f(x) = x2 – 1, and g(x) = x + 2, then g(f(x)) = [ ? ]x2+[ ]x + [ ]

Mathematics
1 answer:
tresset_1 [31]4 years ago
7 0
The Answer
Is
Is
Is
Is
Is

0
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N76 [4]
I believe it could be either B or D. 

8 0
4 years ago
Read 2 more answers
Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)
JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

6 0
3 years ago
What was the day of the week on Alex’s 39 day of his trip
vitfil [10]

Answer:

what year was his trip? I can figure it out I just need the year

Step-by-step explanation:

6 0
4 years ago
Simplify the expression ​
finlep [7]

Answer:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}

Step-by-step explanation:

We have the expression:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x}

The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x

We will get:

(\frac{2}{2} )\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x}

Now we can directly add the terms to get:

\frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x}  = \frac{x - 6}{4*x}

We can't simplify this anymore

3 0
3 years ago
The point-slope form of the equation of a line that passes through points (8,4) and (0, 2) is y-
Oksi-84 [34.3K]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

While the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}):It is a point through which the line passes

In this case we have a line through:

(8,4) and (0,2)

Therefore, its slope is:

m = \frac {2-4} {0-8} = \frac {-2} {- 8} = \frac {1} {4}

Its point-slope equation is:

y-4 = \frac {1} {4} (x-8)

Then, we manipulate the expression to find the equation of the slope-intersection form:

y-4 = \frac {1} {4} x- \frac {8} {4}\\y-4 = \frac {1} {4} x-2\\y = \frac {1} {4} x-2 + 4\\y = \frac {1} {4} x + 2

Therefore, the cut-off point with the y-axis is b = 2

ANswer:

y = \frac {1} {4} x + 2

7 0
3 years ago
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