This question is quite similar to the one earlier, so we will be using SOH CAH TOA again.
We first have to calculate the length of CB. All we have to do for this is use Pythagoras's theorem.
√12² - 6²
= 10.39230... cm
Now we use SOH CAH TOA for the next part.
Lets label the sides.
CB is the opposite
CD is the hypotenuse
We will use sin, since we know the angle, the opposite and we want to know the hypotenuse.
sin(55) = opp / hyp
sin(55) = 10.39230... / x
10.39230.. / sin(35) = x (you re-arrange the equation to get x alone)
12..68666.. = x
So x = 12.687 to 3 significant figures
1) False
2) True
3) True...I think
4) False
Answer: The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.5, 2). The finishing point will be at (2, −5.5).
I believe you are asking in how many ways they can sit. If so:
The 1st can sit anywhere: he has only 1 way to sit
The 2nd can sit in 11 ways, since one seat is already occupied
The 3rd can sit in 10 ways, since 2 seat are already occupied
The 4th can sit in 9 ways, since 3 seat are already occupied
The 5th can sit in 8 ways, since 4 seat are already occupied
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The 12th can sit in 1 way, since11 seat are already occupied
General formula for a circular table:
Number of ways they n persons can be seated: (n-1)!
and the 12 can be seated in (12-1)! = 11! = 39,916,800 ways.
This is called circular permutation