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morpeh [17]
3 years ago
9

The point-slope form of the equation of a line that passes through points (8,4) and (0, 2) is y-

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

While the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}):It is a point through which the line passes

In this case we have a line through:

(8,4) and (0,2)

Therefore, its slope is:

m = \frac {2-4} {0-8} = \frac {-2} {- 8} = \frac {1} {4}

Its point-slope equation is:

y-4 = \frac {1} {4} (x-8)

Then, we manipulate the expression to find the equation of the slope-intersection form:

y-4 = \frac {1} {4} x- \frac {8} {4}\\y-4 = \frac {1} {4} x-2\\y = \frac {1} {4} x-2 + 4\\y = \frac {1} {4} x + 2

Therefore, the cut-off point with the y-axis is b = 2

ANswer:

y = \frac {1} {4} x + 2

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