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babunello [35]
3 years ago
11

The blood mass of a mammal is proportional to its body mass. A rhinoceros with body mass 3000 kilograms has blood mass of 150 ki

lograms. Find a formula for the blood mass, M, of a mammal as a function of the body mass, B, and estimate the blood mass of a human with body mass 80 kilograms.
Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

The equation which equates the two is M  = \frac{B}{20}  = 0.05B

A human with a body mass of 80 kilograms will have a blood mass of 4 kilograms.

Step-by-step explanation:

It is said that the blood mass is proportional to the body mass.

We can say that the blood mass of a mammal is M, and that the body mass of a mammal is B.

Since the two are proportional we can write

M  ∝ B   , or M = kB    where k is the constant of proportionality.

Using the given values for a rhinoceros we can write

150 = k × 3000

Therefore k = \frac{150}{3000} = \frac{1}{20}  = 0.05

Therefore the equation which equates the two is M  = \frac{B}{20}  = 0.05B

A human with a body mass of 80 kilograms will have a blood mass of

= \frac{80}{20}  = 4 kilograms

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Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




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Step-by-step explanation:

Given

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andreyandreev [35.5K]

Answer:

18+12.125π units²

Step-by-step explanation:

The diameter of the semicircle can be found by the use Pythagoras theorem.

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