2 years ago

How would you multiply (3x-8)(2x^2+4x-9)

1 answer:

4 0

(3x-8)(2x^2+4x-9)= 6x^3−4x^2−59x+72
Hope I helped! ( Smiles )

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2 years ago

Put brackets in the calculation below to make it correct. 15 - 4 x 2 + 1 = 3

bagirrra123 [75]

If you put brackets around (2+1), your method of working is:
1) 15-4*(2+1)=3
2) 15-4*3=3
3) 15-12=3
You don't need any more brackets, as the BIDMAS (brackets, Indices, division, multiplication, addition, subtraction) rule does the rest of the job for you.
The answer is therefore: 15-4*(2+1)=3

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2 years ago