7x-99=2x+1
5x=100
x=20
mark me brainliest if the answer is correct, thank you in advance :)
Diagram? There is no diagram given.
a.
Cannot solve b without the diagram.
Answer:
2100
Step-by-step explanation:
There are 21 consonants that can serve as the first and last letters. There are 5 vowels that can serve as the 2nd and 4th letters. There are 20 remaining consonants that can serve as the 3rd letter. (The same consonant cannot appear in all three places.)
So, the total number of 5-letter palindromes that start with a consonant and alternate with a vowel will be ...
21×5×20 = 2100 . . . different palindromes