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3 years ago

What are three different reasons why people access networks? Give an example of each reason

1 answer:

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Communication: Communication is one way to be connected to the network and use the internet. It helps maintains communication with other network users. A few examples include email, IM services, video conferencing, Skype and many more.

File sharing: Easily sharing files and data. From businesses to schools to friends, everyone sends files to through internet and this has become an essential part of life. Various services like Gmail and yahoo mail are used.

Social networking: This is an essential medium to communicate with friends and family members. Examples include Facebook, Twitter, and Instagram.

You might be interested in

How many accelerometers are there in an IRS system?

slega [8]

The number of accelerometers that are in an IRS system are three (3).

<h3>What is an IRS system?</h3>

IRS system is an abbreviation for inertial reference system (IRS) and it can be defined as a navigation system that is designed and developed to provide inertial navigation data to various user systems, especially by using a ring-laser gyro.

In the Aviation and Engineering filed, he number of accelerometers that are in an inertial reference system (IRS) system are three (3).

Read more on navigation system here: brainly.com/question/26052911

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5 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Find the quotient and the remainder of 11010111 ÷ 1010, assuming that the binary numbers are signed integers in two's complement

andrew-mc [135]

Answer:

Answered

Explanation:

$(11010111)_2= -32+8+2+1$ = -21

value of 21 = $(010101)_2$

$(100111)_2$ = -32+4+2+1= -24

value of 25 = (011001)_2

$-21\times -25 = 525$

$525 = (001000001101)_2$

5 0

3 years ago

Why are wiki's not secure

Nookie1986 [14]

Wikipedia is not a reliable source for citations elsewhere on Wikipedia. Because, as a user-generated source, it can be edited by anyone at any time, any information it contains at a particular time could be vandalism

7 0

2 years ago

Which answer choice correctly distinguishes among the three pieces of data?

wolverine [178]

Answer:

a. 1 is a packet, 2 is data, 3 is a frame.

Explanation:

And what is not mentioned is segment which used TCP/UDP and is part of Transport layer. The packet carries the destination and sender IP address, and is part of the Network Layer. The frame has the Mac address of destination device and senders device and is part of data link layer.

Hence segment has no IP address, hence b. is not correct. Also, data cannot have the IP Address, and Frame has the MAC address, Hence, the above answer. And this arrangement is part of Data Encapsulation.

Also keep in mind data can be anything like a series of bits, or any and it can or not have a header.

7 0

3 years ago