These materials are called conductors
Here is a somewhat cryptic solution that works:
#include <algorithm>
#include <cstdlib>
using namespace std;
void q(char c, int count)
{
for (int i = 0; i < count; i++) {
putchar(c);
}
}
void p(int b1, int plusses)
{
q(' ', b1);
q('+', plusses);
}
int main()
{
for (int i = -3; i <= 3; i++)
{
int pl = min(6, (3 - abs(i)) * 2 + 1);
p(6-pl, pl);
i == 0 ? p(0, 6) : p(6, 0);
p(0, pl);
putchar('\n');
}
getchar();
}
Your answer would be true, (brainliest answer please)
Answer:
public class Leo{
public String method1(){
return "Jack 1 Leo 1";
}
public String method2(){
return "Don 2 Jack 2";
}
public String method3(){
return "Jack 3 Leo 3 Don 2";
}
public String toString(){
return "Jack 3 Leo 1"
}
}
public class Jack extends Leo{
}
Explanation:
Leo is the parent class and jack inherits all of its attributes from Leo
So when you call the following code in the main method:
Jack j = new Jack();
System.out.println(j.method1);
it should print Jack 1 Leo 1
This is because the program first checks if method 1 exists in the Jack class
Because it doesn't exist it then goes to the parent class which is Leo.
And in the Leo class method1 displays "Jack 1 Leo 1 "
So it prints that
Answer:
o·vo·vi·vip·a·rous
Explanation:
(of an animal) producing young by means of eggs which are hatched within the body of the parent, as in some snakes.
