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3 years ago

Determine which of the four levels of measurement (nominal, ordinal, interval, ratio) is most appropriate. brands of cereal

1 answer:

8 0

This is an example of a nominal level of measurement.

In a nominal level of measurement, we are just classify the type of a variable. In this case, we are assigning a specific brand type to a particular cereal.

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Solve the system of equations. −4x+3y=−2 y=x−1 x- y-

Kobotan [32]

Answer: x= -1

y= -2

Step-by-step explanation:

-4x+3y= -2

y=x-1

-------------------

-4x+3(x-1)= -2

-4x+3x-3= -2

-x=1

x= -1

y=-1-1

y=-2

6 0

3 years ago

Read 2 more answers

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Simora [160]

Answer:

option B

Step-by-step explanation:

Top right graph

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3 years ago

Read 2 more answers

A piece of machinery depreciates $5000 the first year,

eimsori [14]

Answer:

A- $3500

Step-by-step explanation:

The depreciation rate is $300

$5000, $4700, $4400

$300 x 3 = 900

$4400 - 900 =

$3500.

4 0

3 years ago

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

3 years ago

Which statement describes ?

Deffense [45]

Answer: B

The series converges because it has a sum of 4.

Step-by-step explanation:

8 0

3 years ago