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vodka [1.7K]
3 years ago
15

Find the measure of the exterior angle.

Mathematics
1 answer:
sammy [17]3 years ago
6 0

Answer:

k =64+76 =140 °

Step-by-step explanation:

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pls help!! A cylindrical vase has a diameter of 12 inches and a height of 12 inches. If the vase is filled 3/4 full of soil, how
il63 [147K]

Answer:

Answer: the vase contains 1017.36 inches³ of soil.

Step-by-step explanation:

We would apply thee formula for determining the volume of a cylinder which is expressed as

Volume = πr²h

Where

h represents the height of the cylinder

r represents the radius of the cylinder.

π is a constant whose value is 3.14

From the information given

Diameter = 12 inches

Radius = diameter /2 = 12/2

Radius = 6 inches

Height = 12 inches

Therefore,

Volume of the cylindrical vase =

3.14 × 6² × 12 = 1356.48 inches³

If the vase is filled 3/4 full of soil, then the volume of soil in the vase is

3/4 × 1356.48 = 1017.36 inches³

7 0
3 years ago
Break the numbers 0-9 into 3 groups. Each group needs to equal the same number when added! Write out the groupsand the sum of ea
Burka [1]

we must do the following:

0

1

2

3

4

5

6

7

8

9

select the major, the minor and the half and add, like this:

9+0+5+1=15

therefore:

7+6+2=15

also:

\begin{gathered} 8+4+3=15 \\  \end{gathered}

the groups are:

(9,0,1,5); (7,6,2); (8,4,3)

8 0
1 year ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
Read 2 more answers
W÷5=? "With work if needed"
Svetach [21]

Answer: This question doesn't have an answer.

Step-by-step explanation:

8 0
3 years ago
Jason is putting in a new circular shaped fire pit in his backyard.The diameter of the fire pit is 8 feet. What is the area of t
lesya [120]
Pi * r^2 = 16pi
Thank you hope this helps
3 0
3 years ago
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