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kirza4 [7]
3 years ago
14

I dont understand this can someone explain it

Mathematics
1 answer:
Olegator [25]3 years ago
3 0
Sorryyyyyy don't know
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At a local restaurant the amount of time that customers have to wait for their food is normally distributed with a mean of 26 mi
konstantin123 [22]

Answer:http://avconline.avc.edu/jdisbrow/ma115/Practice%20Test%203%20with%20answers.pdf

Step-by-step explanation:

you welcome

6 0
3 years ago
15Points!!<br> Factor completely.<br><br><br> 12x² +28x
Zigmanuir [339]

Answer:

4x(3x+7)

Step-by-step explanation:

12x^2+28x\\12xx+28x\\\\4\cdot \:3xx+4\cdot \:7x\\4x\left(3x+7\right)

4 0
3 years ago
- 5.8c + 4.2 - 3.1 + 1.4c − 5.8c + 4.2 − 3.1 + 1.4c
Cerrena [4.2K]

Answer:

-8.8c + 2.2 OR SOLVED c = 0.25

Step-by-step explanation:

<u>Step 1:  Combine like terms</u>

- 5.8c + 4.2 - 3.1 + 1.4c − 5.8c + 4.2 − 3.1 + 1.4c

<em>-8.8c + 2.2</em>

<em />

<u>Step 2:  If needed solve for c</u>

-8.8c + 2.2 - 2.2 = 0 - 2.2

-8.8c / -8.8 = -2.2 / -8.8

<em>c = 0.25</em>

<em />

Answer:  -8.8c + 2.2 OR SOLVED c = 0.25

8 0
3 years ago
Read 2 more answers
Jose Rivera purchased 7 textbooks for his classes at River Run Community College. The total cost of the texts was $208.55. What
shepuryov [24]
In the question, there are certain information's that are of immense importance in regards to finding the answer. The first information is that Jose Rivera had purchased 7 textbooks for his classes at River Run Community College. The price that Jose Rivera had to pay was $208.55. The average cost per textbook needs to be found.
The cost of 7 textbooks purchased by Jose Rivera = 208.55 dollars
Then
The cost of 1 textbook purchased by Jose Rivera = (208.55/7) dollars
                                                                               = 29.79 dollars
The average cost of a textbook purchased by Jose Rivera rounded to the nearest cent is 29.80 dollars.
6 0
3 years ago
What is the expression to find the distance between the points A and T
navik [9.2K]

Answer:

<h2>9</h2>

Step-by-step explanation:

The <u>square root </u>of

d=(x2​−x1​)^2+(y2​−y1​)^2​

A=(2,5) coordinates 1

T=(5,5) coordinates 2

So we put (5-2)^2 plus (5-5)^2

(3)^2+(0)^2

9+0

9

<h3><u>Brainliest please!</u></h3>
6 0
4 years ago
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