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3 years ago

13

Pls help quick i beg please,Complete the explanation blank and blank 1 whole stirp could represent 1 blank and the 1/3 strip cou

ld represent blank. please help like please cause if you do it i make you The Brainliest

1 answer:

yKpoI14uk [10]3 years ago

4 0

Answer:

Feet and yards; the 1 whole strip could represent 1 yd. and the $\frac{1}{3}$ strip could represent feet.

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Item 5 Solve for b. − 1 3 b=9 What is the answer?

snow_lady [41]

Answer:

b = -27

Step-by-step explanation:

-1/3 b = 9

Multiply each side by -3

-3 * -1/3 b = -3 * 9

b = -27

7 0

3 years ago

Read 2 more answers

How many minutes does it take the duck to fly 1 kilometer?

sashaice [31]

Answer:

4

Step-by-step explanation:

In 3 mintues the duck goes 12 kilometers. 12 divided by 3 is 4. I take 1 mintues to go 4 kilometers.

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2 years ago

Express each rate as a unit rate. 720 miles traveled on 60 gallons of gasoline=

Brut [27]

720 miles traveled on 60 gallons of gasoline.
Express this on its Unit Rate.
To get the answer, we need to divide 720 miles by 60 gallons of gasoline
=> 720 / 60 = 12 miles /gallons
Thus, in every 1 gallon of gasoline, you can travel 12 miles.
So, the expression would be like this:
720 miles / 60 gallons = 12 miles / gallon
Let’s check our answer
=> 12 miles x 60 gallons = 720 miles.
Thus, we got the correct answer.

7 0

3 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

17. Evaluate each pair of expressions.<br> a. (-3)-8 and -3-8<br> b. (-3)-9 and -3-9

Semmy [17]

A = -11
B= -12

This is because of how calculations work in negatives. Because they are both negative they work similarly to addition

5 0

3 years ago