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joja [24]
1 year ago
10

The 10th graders are having a bake sale to raise money for their homecoming float. If they sell c cupcakes and p cake pops at th

e prices shown below, then the amount of money raised is given the expression 0.75c+0.5p
Mathematics
1 answer:
Tomtit [17]1 year ago
4 0

The amount of money raised by the 10th graders at the bake sale using the expression 0.75•c + 0.5•p, selling 60 cupcakes and 75 cake pops is $82.5

<h3>Which method can be used to calculate the sales of the 10th graders?</h3>

The expression for the amount of money raised is <em>M </em>= 0.75•c + 0.5•p

From a similar question posted online, the amount of money raised where for example 60 cupcakes and 75 cake pops are sold is required.

Based on the equation, the selling prices are;

Cupcakes, <em>c</em> = 75¢

Cake pops, <em>p</em> = 50¢

The amount of money raised is therefore;

  • M = 0.75•c + 0.5•p

M = 0.75 × 60 + 0.5 × 75 = 82.5

Therefore;

  • The amount of money raised is <em>M </em>= $82.5

Learn more about equations here:

brainly.com/question/22688504

#SPJ1

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Answer:

C 44.59

Step-by-step explanation:

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                =133.77

We want to find the mean cost (average cost)

Take the total cost and divide by the number of shirts

133.77/3 =44.59

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Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

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We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

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